3x +5 8. Find the inverse of the function g(r)- 4 -1 a.3 g" (x)=4x+5 4...
14. Find the inverse function of f(x) = (x-5)3 f-1x= 3x -5 f-1x= 3x +5 f-1x= x+5 f-1x= 3x +125 f-1x= 3x -125 15. Find the center and the radius of the circle (x-4)2+(y+3)2 =64. (4, -3), r = 8 (-3, 4), r = 8 (-4, 3), r = 64 (-3, -4), r = 64 (-4, -3), r = 64
(c) Find a formula for the inverse of the function. 4x-1 ) f(x) _[3 marks] 2x+3 (ii) f(x) = /10 - 3x [2 marks) 1+1 (111) g(x) = 1-e* [3 marks] Total: 25 marks!
3) Complete the Partial Fractions and find the indefinite integral r-3x5 +4x4 +2x3 10x2 +4x +8 x3(x 1)2(x +2)2 dx 3) Complete the Partial Fractions and find the indefinite integral r-3x5 +4x4 +2x3 10x2 +4x +8 x3(x 1)2(x +2)2 dx
find the inverse of f-1(x) of the function f(x)= ^3 root x-5 3) find the inverse f(x) of the function, f(x) = 3JX-5 3x = 14-5 deel X² = Jy - 5
A3.1. Given a function (g(x)=\begin{cases} \dfrac{3x^2+4x-4}{3x-2}, { x \neq \dfrac{2} {3} \\ \\ \dfrac{8}{3}, & x = \dfrac{2}{3} \end{cases} V). Check whether it is continuous at \( x = \dfrac{2}{3} V) and justify your answer with necessary steps.
Show work thumbs up VII. Functions Find the Domain of each function. f(x)--/-x2-4x + 5 g(x)-In(4t-3) a) b) e) h(x)- +3x2 -x-3 Find the zeros, vertical asymptotes, and horizontal asymptotes f(x) = 3x"-14x-5 (4x-17x-15 6x2 -7x-5 f(x) = -12 万 b) Transformations a) Beginning with f(x)- Vx, find the function g(x) that shows fcx) shited to the let 2 units, reflected over the x-axis, and then shifted up 7 units. b) Beginning with f(x)find the function g(x) that shows f(x)...
4x-3 The function g is defined by g(x) = x+1 Find g(n+3). 8 (n + 3) = 1 xo?
Compute the inverse function of each of the following bijections. a. f: R → R,f(x) 4x + 7 ,b,f: (0,oo) → R,f(x)-log8x + 5 c. f: R → R,f(x)--7(x-2)3 + 11, d. f: RM0)-A(0), f(x) = x
x-4 7. Pax- 8. 4x-y=3 (3x +2y=-18 10. 1, y=2x-4 12.13x+4y-8 r=-4
Which function below is the inverse of f:R-{2} → R-{3} ut of f(x)= -3x+1 X X-2 Select one: O a. f-1: R-{3} → R-{2} f'(x)=2x+1 X-3 O b. f-1: R - {2} → R-{3} F"(x) = 2X+1 X-3 f-:R-{2} → R-{3} f(x)= x-2 3x + 1 O d. f-1: R - {3} → R-{2} ... X-2 hook....pdf - POS Week 171 ..hantal ob. F-R-{2} → R-{3} F-1(x)=2x+1 3 F-1R- {2} → R - {3} X-2 pe d. f":R-{3} → R...