Question

2. What is the value of x alter the following code is executed # include<iostream> using namespace std; int main int t-0, c- 0,x-3; while (c < 4) t=t+x; cout << x return 0; a) 3 b) 21 c) 24 d) 48 3. What is the output of the following code? # include<iostream> using namespace std; int main0 int a- 3; for (int i 5; i >0; i) a a+i cout << a << “ “ return 0; d) 8 1215 17 18 18 a) 7 10 12 13 b)7 10 12 13 13 e)8 12 15 17 18

Answer 1

Here initially x = 3 & C = 0 for 1st iteration C < 4 x = x times 2 therefore x = 6 & C = 1 for 2nd iteration C < 4 x = x times 2 therefore x = 12 & C = 2 for 3rd iteration C < 4 x = x times 2 therefore x = 24 & C = 3 for 4th iteration C < 4 x = x times 2 x = 48 & C = 4 for 5th iteration C not < 4 therefore Loop ends therefore x = 48 Here initially a = 3 & I = 5 for 1st iteration I > 0 therefore a = 3 + 5 = 8 & I = 4 for 2nd iteration I > 0 therefore a = 8 + 4 = 12 & I = 3 for 3rd iteration I > 0 therefore a = 12 + 3 = 15 & I =