Please give me the exact rounded answer
Solution :
Given that,
= 0.28 =28%
1 - = 1 - 0.28 = 0.72
margin of error = E = 4% = 0.04
At 90% confidence level z
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645 ( Using z table ( see the 0.05 value in
standard normal (z) table corresponding z value is 1.645 )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (1.645 / 0.04)2 * 0.28 * 0.72
=340.95
Sample size =341
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