Homework Answers
Sb4 + 6 Cl2 ---> 4SbCl3
Moles of Sb4 = 4.50/487.2 => 0. 00924 mol
Moles of Cl2 = 3.25/71 => 0.0458 mol
a) Cl2 is limiting reagent.
b) mass of SbCl3 = 228.15×4×3.25/6×71 => 6.96 g
c) % yield = 4.85×100/6.96
=>69.7 %
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Please show all work for the following problems, not just answers. Will thumbs up upon completion,...
Please show all work
for the following problems, not just answers. Will thumbs up upon
completion, thank you! :)
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Please show all work
for the following problems, not just answers. Will thumbs up upon
completion, thank you! :)
Direction - Please show your work for the following problems. (you may need to answer on separate sheet of paper) Part I- Calculate molecular weight (molar mass). Na2SO4 = Feso, . 71120- HC HO: Part VII- Limiting reagent problems. Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction a) Identify limiting reagent b) How many grams of...
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chlorine according to the following reaction:
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Use the correct number of significant figures, fill in the
number ONLY!
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