Question

2) Solve for X. _3.66205_ 1.40 2.00 Step 1 use.75 R and 62° to find hypotenuse .84943. TYP Step 2 use the 1.4 and subtract .84943 to get .5507. Use this and the 2.0 to get the hypotenuse 2.07440 and both angles 74.08° and 15.399 Step 3 Solve for the oblique using the 2.07440, 3.8 (4.55 - .75) and 43.39° (74.08º and 62° subtracted from 180). Also get the 114.58° angle. 4.55 R .75 R Step 4 Use 3.8 and the now known angle of 50.025° (15.39° and 114.589 from 180°) to solve for the 2.91205 dim. Just add the .75 radius for the answer 3.66205.

What do you mean?

Answer 1

Solution- 1.40 620 C10.75REV 2.00 TYP 4.55R OSR I will provide you the explaination of all the Steps involved in finding x, and also the related calculation. Please refer to the above figure for notations - in o ABC - LABC = 62° ( corresponding Angle ) of LAC B = 90° (As CA is parallel to FG) & AC=0.75 (As AC is parallel to FG) Scanned with CamScanner

ALUL As we know that - Sine: perpendicellan Hypotenuse Here, sino = AC AB AB = AC O sind AB= 0.75 din 62 AB= 0.84943 Step 2 - BDƏ AD - AB [7A0 = 1.40 ] = 1.40 - 0.84943 BD = 0.5507 Now, in O BDE - BE2, BD?+ DE? (;Using Pythagoras Theorem? BE? (0:55077702 BE? 4.3032 BE = 2.07 4401 for LDBE - . BE Bubuo 2.07440 Sin (COBE) 0196413 TLDBE: 74.60 9 LBED = 180° - 900- 74.60° Sin (LDBL) - DE CS Scanned BED = 15.390 CamScanner

Step3- LEBF = 1809–LDBE - LABF = 180°-74.60 -62° | EBA = 43.407 is Mlaw, in DBef= BE = 2.0744 Ef = 455&-0.75R EF = 3.81 using sine Rule in SB Ef= sing - Some a serie But Here, b-EF3.8 Sinbo Sin (LEBF) = 43.40 e = Bf : ? sine = Bi'n CLBEF) f - BE = 2.0744 sinf Sin (LBFE) Solving ear now 3.8 e 2.0744 sing - sine sinf - sinB = 43.40 [ from egn. cz 3) sinf - .0744x Sin 43.4° Scanned with CamScanner

LBPE = 22.0280 3 ZBEF = 180° – LEBF - CBFE =) <BEF = 180°- 43.40 – 22.028° ><BER = 114.5897 Step 4- Now, in a EfH- CHEF = 180°-LDEB – LBEF = 180° - 15.399 – 114.58° | CHEF = 50.0301 to calculate the length of Mf, using sin funetion- Sinhef) = Perpludicular (P) Hypotenuse CHD elin (LHEF) = HF EF a) HF - EF Xabin (LHEF) CARS = 3.8 x Sin (50.039) L THE= 2.912 2 And - r = HF +0.758 3) 2=2.9122+0.75 2= 3.6625 Scanned with CamScanner