Question

Imagine 4 different objects with the same coefficient of static friction µs. Use the system to set and test these 4 masses. Rank in order from smallest to largest: the minimum applied force required to make the objects move if their masses are:
Object 1 = m/2        Object 2 = m        Object 3 = 2m        Object 4 = 4m

Now imagine that the objects in the question above are pushed with a force F for 4 seconds each. Rank, from smallest to greatest, the final velocity of the objects. Explain.

Answer 1

# a The frictional force f = ls N. N- Normal force on object. N = Mg! If = Us Mg! so friction force is directly depends proportionally on the mass of object, so friction will be. greatest on Object 4 =40 follow by The order of minimum force required to mowe Horm. object t < <object 3 <object 4 When force f' is applied in these y objects aculararon as as others, so object 2 1 their will be las F-€ = F-ung M az - ug M enpression So from above we can say the more the mass of object less the accelaratia and less the final speed. so order is. object 4 Lobject 3c object 2 s object!

# a The frictional force f = ls N. N- Normal force on object. N = Mg! If = Us Mg! so friction force is directly depends proportionally on the mass of object, so friction will be. greatest on Object 4 =40 follow by The order of minimum force required to mowe Horm. object t < <object 3 <object 4 When force f' is applied in these y objects aculararon as as others, so object 2 1 their will be las F-€ = F-ung M az - ug M enpression So from above we can say the more the mass of object less the accelaratia and less the final speed. so order is. object 4 Lobject 3c object 2 s object!