Question

Explain the ANOVA Descriptives Test of Homogeneity of Varian Post Hoc Tests Multiple Comparisons Dependent Vantie Bench Press TSD Wan De Code Co J S ME S 23 21000 1.04808 000 Torch 47.70000 1.04308 71.92000 1.04808 95% Confidence interval Lower Bound Upper Bound 20.5000 259140 449960 504040 89 2160 746240 -20.5060 -23 21000 1.04B0B 271940 Torch Power -4770000 1 DEBOR -2449000 24 22000 100 Power -192000 10B SI -48.71000 10408 Torch -24 22000 1.04808 The mean oference is significant at the level 51.4140 -449960 - 21.00 269240 -892180 000 000 0 00 -746240 -51.4140 28.9240 -21.5160 • Homogeneous Subsets ANOVA Bench Press Sum of Squares 288637828 21749 770 910387598 F 1751.752 Between Groups Within Groups Total Mean Sure 95212.609 5 4924 Sig 000 3 3 96 399 Bench Press Thay HSD" Substrata005 642100 Bumn Torch 100 100 4700 1129200 1000 1 000 1 000 1000 Means for groups in homoges Subsets are displayed a Uses Harmonic Mean Sample 100 000

Answer 1

Null and alternative hypothesis for ANOVA: Ho: Mpower = Uskill = | Torch Burn HA:Not all population means are equal. The value of test statisticis, F=1751.752 The p-value is 0.000 Conclusion: The p-value of F test is less than 0.05. Hence we reject null hypothesis at 5% level of significance and conclude that there is difference in the average maximum effort on bench press between the various weights oftraining programs. Conclusion of Tukey HSD test: (multiple Comparisons test) By using the p-value of Tukey HSD test we can compare mean difference between various weights of training programs. There is difference in the average maximum effort on bench press between: 1) Power and Skill (P-value is 0.000. This is less than 0.05) 2) Power and Torch (P-value is 0.000. This is less than 0.05) 3) Power and Burn (P-value is 0.000. This is less than 0.05) 4) Skill and Torch (P-value is 0.000. This is less than 0.05) 5) Skill and Burn (P-value is 0.000. This is less than 0.05) 6) Torch and Burn (P-value is 0.000. This is less than 0.05)