Question

The equilibrium constant K for a certain reaction was measured as a function of temperature (in Kelvin). A plot of ln(K) versus 1/T for this reaction gives a straight line with a slope of 1.352 x 104 K and a y-intercept of -14.51. Determine the value of AHo for this reaction 120.6 kJ/mol 164.7 kJ/mol 112.4 kJ/mol 176.7 kJ/mol none of the above

0 0
Add a comment Improve this question Transcribed image text
Answer #1

The answer is -112.4 kJ/mol

Explanation

This is graph is called Van't Hoff plot

lnKeq = - ∆H°/RT + ∆S°/R

Slope = - ∆H°/R

∆H° = - slope × R

= - (1.352 ×10^4 K × 8.314 ( J/K mol )

= - 1.124 × 10^5 J/ mol

= - 112.4 kJ / mol

Add a comment
Know the answer?
Add Answer to:
The equilibrium constant K for a certain reaction was measured as a function of temperature (in...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT