The rate constant for a reaction is measured as a function of time. A plot is created by graphing ln(k) on the y-axis and 1/T on the x-axis, and a best fit line with a slope of -83,871 K is obtained. Based on this data what is the activation energy of this reaction (in kJ/mol)?
R= 8.314 J/(K mol)
The rate constant for a reaction is measured as a function of time. A plot is created...
The activation energy for a particular reaction is 102 kJ/mol. If the rate constant is 35 × 10⁻⁴ s⁻¹ at 322 K, what is the rate constant at 273 K? An experimental plot of ln(k) vs. 1/T is obtained in lab for a reaction. The slope of the best-fit line for the graph is -3090 K. What is the value of the activation energy for the reaction in kJ/mol?
The equilibrium constant K for a certain reaction was measured as a function of temperature (in Kelvin). A plot of ln(K) versus 1/T for this reaction gives a straight line with a slope of 1.352 times 10^4 K and a y-intercept of -14.51. Determine the value of Delta H degree for this reaction -120.6 kJ/mol -164.7 kJ/mol -112.4 kJ/mol -176.7 kJ/mol none of the above
The rate of a reaction was measured as a function of time and the data was plotted as shown in the figure below. The slope of the plot is -5.17 × 10 K. The y-intercept is -1.69. What is the activation energy of the reaction? The answer is 43.0 kj/mol, probably rounded In-k
the rate constant (k) for a reaction was measured as a function of temperature. A plot of lnk versus 1/T(in K) is linear and has a slope of -9.90•10^3 K. calculate the activation energy for the reaction.
1) Calculate the activation energy in kJ/mol for the following reaction if the rate constant for the reaction increases from 93.5 M-1s-1 at 497.7 K to 1349.3 M-1s-1 at 636.7 K. do not include units, but make sure your answer is in kJ/mol! 2) A chemist constructs a plot of ln k vs. 1/T for a chemical reaction. The slope of the trendline for the data is -746 K. What is the activation energy for this reaction in kJ/mol? R...
A chemical reaction was conducted at several different temperatures (measured in K) and the equilibrium constant was measured at each one. Plotting the data on a graph with ln K on the y-axis and 1/T on the x-axis gives a linear plot with slope = -4594.6 and y-intercept = 13.6. What is ΔrH° (in kJ mol-1) and ΔrS° (in J mol-1 K-1)?
The rate constant (k) for a reaction was measured as a function of temperature. A plot of lnk versus 1/T(in K) is linear and has a slope of −1.12×104 K . Calculate the activation energy for the reaction. Express your answer using three significant figures with the appropriate units.
The rate constant (k) for a reaction was measured as a function of temperature. A plot of lnk versus 1/T(in K) is linear and has a slope of -7893 K . Part A Calculate the activation energy for the reaction. Express your answer to four significant figures and include the appropriate units.
The rate constant (k) for a reaction was measured as a function of temperature. A plot of lnk versus 1/T(in K) is linear and has a slope of −1.30×104 K . You may want to reference (Page) Section 14.5 while completing this problem. Calculate the activation energy for the reaction. Express your answer using three significant figures with the appropriate units.
Item 32 The rate constant (R) for a reaction was measured as a function of temperature. A plot of In k versus 1/T'(in K) is linear and has a slope of -6075 K Y Part A Calculate the activation energy for the reaction. Express your answer to four significant figures and include the appropriate units. MA ? E.- Value Units Submit Request Answer Provide Feedback