Question

a report announced that the median sales price of a new houses sold one year was 221,000 and the mean sales price was 273,000. assume that the standard deviation of the price us 90,000.

complete A-D with full work please so i may know how to do in the furture

A report announced that the median sales price of new houses sold one year was $221,000, and the mean sales price was $273,000 tf you select samples of n#2, describe the shape of the sampling distribution ofX. Choose the correct answer below O A. The sampling distribution is skewed to the right, but less skewed to the right than the population. B. The sampling distribution will depend on the specific sample and will not have a constant shape. O C. The sampling distribution will be approximately uniform O D. The sampling distribution will be approximately normal. if you select samples of n-100, describe the shape ofthe sampling distrbution of X. Choose the correct answer below O A. The sampling distribution is skewed to the right, but lessed skew to the right than the population. O B. The sampling distribution will be approximately normal. O C. The sampling distribution will be approximately unifomm O D. The sampling distribution will depend on the specific sample and will not have a constant shape. If you select a random sample of n 100, what is the probability that the sample mean will be less than $300,000 The probability that the sample mean will be less than $300,000 is (Round to four decimal places as needed.) If you select a random sample of n 100, what is the probability that the sample mean will be between $275,000 and $285,000 The probability that the sample mean will be be between $275,000 and $285,000 is Round to four decimal places as needed) Cick to select your answerls) 4

Answer 1

a) n=2 is a very small sample size, so the sampling distribution will depend on the specific sample and not have a constant shape

b) For n=100, from the central limit theorem we know that X bar will have a sampling distribution ie approximately normal.

c) The parameters of the sampling distribution will be u= 273000 and sigma= 90000/√100 = 9000

So, P(X<300000) = P(Z<300000-273000/9000) = P(Z<3) = 0.9987

d) P(275000<X<285000) = P(0.22<Z<1.33) = P(Z<1.33) - P(Z<0.22) = 0.9082-0.5871= 0.3211