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In an ammonia solution, the silver ion, Ag, forms the colorless, but soluble diamminesilver(I) complex ion,...
all 5&6 5.) Solid silver bromide , AgBr, can be dissolved by adding concentrated aqueous ammonia to give the water- soluble silver-ammonia complex ion. AgBr(s) + 2NH,(aq) U Ag(NH), (aq) + Br(a...
all 5&6
5.) Solid silver bromide , AgBr, can be dissolved by adding concentrated aqueous ammonia to give the water- soluble silver-ammonia complex ion. AgBr(s) + 2NH,(aq) U Ag(NH), (aq) + Br(aq) (a) Show that this equation is the sum of two other equations, one representing the dissolution of AgBr into its component ions and the other representing the formation of the silver-ammonium complex from silver ion and ammonia (b) Calculate the equilibrium constant for the above reaction K,(AgBr) =...
2. With the precipitate (AgCl) still present in the test tube, add aqueous ammonia. The precipitate...
2. With the precipitate (AgCl) still present in the test tube, add aqueous ammonia. The precipitate should disappear. This means that silver chloride is soluble in ammonia solution. It is soluble because silver ion and ammonia form a complex called diamminesilver (I) chloride, [Ag(NH3)2]Cl which in solution exists as [Ag(NH)2]* and Cl ions. You could have guessed that this would have happened if you looked over the Table A values of Kr at the end of this lab (and you...
Review equation 16.10 and step B2. Ag+1(aq) and NH3(aq) will form a soluble complex ion. Use...
Review equation 16.10 and step B2. Ag+1(aq) and NH3(aq) will form a soluble complex ion. Use rule 3 of Water-Insoluble Salts in Appendix E to determine what would happen if Ag+1(aq) was combined with KOH instead of NH3. Write the net ionic equation with phase subscripts, where K+1 is a spectator ion which is cancelled out. Equation 16.10: Ag^+(aq) + Cl^-(aq) ⇄ AgCl(s) ⇅ 2NH3(aq) [Ag(NH3)2]^+(aq) Step B2: Silver Chloride equilibrium. To the clear solution from part B.1, add 5...
Another form of this equation (called the complete ionic equation) indicates the species that are actually...
Another form of this equation (called the complete ionic equation) indicates the species that are actually present in solution. 2Na+ + CO32-+2hr + 2 cr . 4 co2 +H2O + 2 Na. + 2 cr Since balanced chemical equations indicate only substances that change, this equation simplifies to This simplified equation is called a net ionic equation. The evolution of CO2 gas is visible as tiny bubbles. Sulfate, so2 Sulfate, So,, is found in compounds such as NaSO4. If a...
Part B please. Part A Silver chloride is only slightly soluble in pure water at 25...
Part B please.
Part A Silver chloride is only slightly soluble in pure water at 25 C AgCI(s) Ag (ag)+CI (aq) K-1.8 x 10 1 Calculate the concentration of Ag and Cl in a solution that is saturated with AgCl e, the system is at equilibrium and there is still solid AgCl visible). Express your answers using two significant figures, separate your answers by a comma. [Ag+],[Cl-)- 1.3×10-5 1.3×10-5 mol Li Previous An Correct Part B The addition of ammonia...
Consider the insoluble compound cobalt(II) carbonate , CoCO3 . The cobalt(II) ion also forms a complex with ammonia . Wr...
Consider the insoluble compound cobalt(II) carbonate , CoCO3 . The cobalt(II) ion also forms a complex with ammonia . Write a balanced net ionic equation to show why the solubility of CoCO3 (s) increases in the presence of ammonia and calculate the equilibrium constant for this reaction. For Co(NH3)62+ , Kf = 1.3×105 . Use the pull-down boxes to specify states such as (aq) or (s). Knet = Consider the insoluble compound silver chloride, AgCl. The silver ion also...
Aluminum ion in solution reacts with water to form aqueous hexaaguaaluminum ()ion. Write this reaction below,...
Aluminum ion in solution reacts with water to form aqueous hexaaguaaluminum ()ion. Write this reaction below, remember phases. Aluminum is more likely to form a hydrated complex than the other four ions remaining in solution, because of its relatively small size and high charge To separate the Group B2 ion, the solution first is made basic by adding ammonia. In the presence of this weak base the pH is adjusted to 9-10 and the group B ions form insoluble hydroxides....
Testbank, Question 17.074 In an aqueous solution silver ions can form Ag(NH3)2+(aq) in the presence of...
Testbank, Question 17.074
In an aqueous solution silver ions can form
Ag(NH3)2+(aq) in the
presence of ammonia. For
Ag(NH3)2+(aq): (see
photo)
Testbank, Question 17.074 In an aqueous solution silver ions can form Ag(NH3)2+ (aq) in the presence of ammonia. For Ag(NH3)2+(aq) Ag(NH3)2+(aq) is a complex ion; NH3 is a donor atom; Ag+ is a ligand Ag(NH3)2+(aq) is an acceptor ion; NH3 is a ligand; Ag+ is a complex ion Ag(NH3)2+(aq) is a complex ion; NH3 is a ligand; Ag+ is...
H. Complex Ions 1. Silver chloride has very low solubility in water (Ks of 1.6 x...
H. Complex Ions 1. Silver chloride has very low solubility in water (Ks of 1.6 x 10-19), however, it is highly soluble in an ammonia solution due to the formation of the complex ion [Ag(NH3)21 (Kr" 1.7 X 10) Given this information, calculate the molar solubility of AgCl in 2.25 M ammonia. 2. Calculate the molar solubility of Cul in 0.92 M KCN. (Ksp of Cul is 1.1 x 10-12, Kp of [Cu(CN)2] is 1.0 x 1016).
Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questions about a saturated solution...
Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questions about a saturated solution prepared by placing solid silver chloride in a 1.94 x 10-5 M NaCl(aq) solution. At some temperature, the silver ion concentration, [Ag+], was found to be 6.24 x 10-6 M. (a) What is the concentration of chloride ions, [CI – ], in the resulting solution? XM (b) What is the molar solubility of silver chloride, AgCl, in 1.94 x 10-5 M NaCl? 4.9 6.24e-6...
all 5&6
5.) Solid silver bromide , AgBr, can be dissolved by adding concentrated aqueous ammonia to give the water- soluble silver-ammonia complex ion. AgBr(s) + 2NH,(aq) U Ag(NH), (aq) + Br(aq) (a) Show that this equation is the sum of two other equations, one representing the dissolution of AgBr into its component ions and the other representing the formation of the silver-ammonium complex from silver ion and ammonia (b) Calculate the equilibrium constant for the above reaction K,(AgBr) =...
2. With the precipitate (AgCl) still present in the test tube, add aqueous ammonia. The precipitate should disappear. This means that silver chloride is soluble in ammonia solution. It is soluble because silver ion and ammonia form a complex called diamminesilver (I) chloride, [Ag(NH3)2]Cl which in solution exists as [Ag(NH)2]* and Cl ions. You could have guessed that this would have happened if you looked over the Table A values of Kr at the end of this lab (and you...
Another form of this equation (called the complete ionic equation) indicates the species that are actually present in solution. 2Na+ + CO32-+2hr + 2 cr . 4 co2 +H2O + 2 Na. + 2 cr Since balanced chemical equations indicate only substances that change, this equation simplifies to This simplified equation is called a net ionic equation. The evolution of CO2 gas is visible as tiny bubbles. Sulfate, so2 Sulfate, So,, is found in compounds such as NaSO4. If a...
Part B please.
Part A Silver chloride is only slightly soluble in pure water at 25 C AgCI(s) Ag (ag)+CI (aq) K-1.8 x 10 1 Calculate the concentration of Ag and Cl in a solution that is saturated with AgCl e, the system is at equilibrium and there is still solid AgCl visible). Express your answers using two significant figures, separate your answers by a comma. [Ag+],[Cl-)- 1.3×10-5 1.3×10-5 mol Li Previous An Correct Part B The addition of ammonia...
Aluminum ion in solution reacts with water to form aqueous hexaaguaaluminum ()ion. Write this reaction below, remember phases. Aluminum is more likely to form a hydrated complex than the other four ions remaining in solution, because of its relatively small size and high charge To separate the Group B2 ion, the solution first is made basic by adding ammonia. In the presence of this weak base the pH is adjusted to 9-10 and the group B ions form insoluble hydroxides....
Testbank, Question 17.074
In an aqueous solution silver ions can form
Ag(NH3)2+(aq) in the
presence of ammonia. For
Ag(NH3)2+(aq): (see
photo)
Testbank, Question 17.074 In an aqueous solution silver ions can form Ag(NH3)2+ (aq) in the presence of ammonia. For Ag(NH3)2+(aq) Ag(NH3)2+(aq) is a complex ion; NH3 is a donor atom; Ag+ is a ligand Ag(NH3)2+(aq) is an acceptor ion; NH3 is a ligand; Ag+ is a complex ion Ag(NH3)2+(aq) is a complex ion; NH3 is a ligand; Ag+ is...
H. Complex Ions 1. Silver chloride has very low solubility in water (Ks of 1.6 x 10-19), however, it is highly soluble in an ammonia solution due to the formation of the complex ion [Ag(NH3)21 (Kr" 1.7 X 10) Given this information, calculate the molar solubility of AgCl in 2.25 M ammonia. 2. Calculate the molar solubility of Cul in 0.92 M KCN. (Ksp of Cul is 1.1 x 10-12, Kp of [Cu(CN)2] is 1.0 x 1016).
Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questions about a saturated solution prepared by placing solid silver chloride in a 1.94 x 10-5 M NaCl(aq) solution. At some temperature, the silver ion concentration, [Ag+], was found to be 6.24 x 10-6 M. (a) What is the concentration of chloride ions, [CI – ], in the resulting solution? XM (b) What is the molar solubility of silver chloride, AgCl, in 1.94 x 10-5 M NaCl? 4.9 6.24e-6...
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