Question

5. The thick biconvex lens shown in air has a radius of curvature of 10,0 em at each surface and the surfaces are 10.0 cm apart. An object 3.00 mm lalk-is placed 5 cm in front of the lens. Use the matrix formulation of optics, Find (a) the location and (b) height of the image. Make a sketch showing the the lens along with the object, image and image location location. n = 1.5 n = 1 10

Answer 1

using Refraction through curved surfan formula N₂= Refractive Index of Refracted Rays man " " Incident Rays For Eist, sunlar 2 Image distanu do= object distanu =-5cm R2 Radius of curvature = +10cm h2=1.5, nel 1.5 t= 1.5-1 mani di = 1 + 1 - 0 de ~5 10 magnificatia Image size = 4x (3mm) dz = 20x15 is alom -3 > 4мм For second surfan> This image will act as object magnification do= -20cm R = -10cm [sign Convention] mz list ho ^2=1, nials Image size=443 = 12mm dito-do dqz hocm M Einal Image=12mm

final (Intermediate imag Image