Homework Answers
The given ANOVA Table is completed as follows:
| Source | Sum of Squares | df | Mean Square | F |
| Between Groups | 2376.8 | 3 - 1 = 2 | 2376.8/2=1188.4 | 21.0659 |
| Within Groups | 846.2 | 18 - 3 = 15 | 846.2/15=56.4133 | |
| Total | 3222.9 | 18 - 1 = 17 |
Correct option:
The three treatment groups differ in SBP.
Explanation:
For Degrees of Freedom (2,15) and 
= 0.05, critical
value of F = 3.682. Since calculated value of F is greater than
critical value of F, reject null hypothesis and conclude that the
three treatment groups differ in SBP..
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