What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Cu(s) and Cr3+(aq) to give Cr(s) and Cu2+(aq) Use the reduction potentials for Cr3+(aq) is -0.74 V and for Cu2+(aq) is +0.34 V. Give your answer using E-notation with ONE decimal place (e.g., 2.1 x 10-2 would be 2.1E-2; and 2.12 x 10-2 would also be 2.1E-2.). Do NOT include spaces, units, punctuation or anything else silly
What is the value of ΔGo in kJ at 25 oC for the reaction between the...
What is the value of ΔG o in kJ at 25 oC for the reaction between the pair: Cu(s) and Cr3+(aq) to give Cr(s) and Cu2+(aq) Use the reduction potentials for Cr3+(aq) is -0.74 V and for Cu2+(aq) is +0.34 V. For these questions, I keep getting a negative answer. The correct answer to this question is 6.3E2, and I put -6.3E2. Why is it a positive number? Isn't the reaction spontaneous?
Question 1) What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Pb(s) and Sn2+(aq) to give Sn(s) and Pb2+(aq) Use the reduction potential values for Sn2+(aq) of -0.14 V and for Pb2+(aq) of -0.13 V Question 2) What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Cr(s) and Cu2+(aq) to give Cu(s) and Cr3+(aq) Use the reduction potentials for Cr3+(aq) is -0.74 V and...
QUESTION 2 What is the value of the equilibrium constant at 25 °C for the reaction between the pair: Ag(s) and Mn2+(aq) to give Agt(aq) and Mn(s) Use the reduction potential values for Ag+(aq) of +0.80 V and for Mn2+(aq) of -1.18 V Give your answer using E-notation with NO decimal places (e.g., 2 x 10-2 would be 2E-2; and 2.12 x 10-2 would also be 2E-2.). Do NOT include spaces, units, punctuation or anything else silly!
Use the standard reduction potentials from the following table to choose the weakest reducing agent among those shown below. Ag+(aq) + - + Ag(s) E° = 0.80 V Cu2+(aq) + 2e → Cu(s) E° = 0.34 V Ni2+(aq) + 2e + Ni(s) E° = -0.26 V Cr3+(aq) + 3e- → Cr(s) E° = -0.74 V Mn2+(aq) + 2e → Mn(s) E° = -1.19 V О Ni(s) Ag(s) Cr(s) Mn(s) Cu(s)
please answer all wueston Question 33 (3 points) (33) For a galvanic cell notation: (-) Ni /Ni2+ (aq) // Au3+ (aq) / Au (+), The electrode potentials: Eº (Ni2+/ Ni) = -0.257 V, E ° (AU3+ / Au ) = 1.498 V. The cell potential Eºcell (a) 1.241 V (b) - 1.755 V O (0) 1.755 V (d) 1.498 Why Question 35 (3 points) (35) For galvanic cell: (-) Cr/ Cr3+ (aq) / Cu2+ (aq) / Cu(+), the correct half...
need answers for all questions Question 35 (3 points) (35) For galvanic cell: (-) Cr/ Cr3+ (aq) // Cu2+ (aq) / Cu (+), the correct half reactions are 0 (a) Cr3+ (a) Cr3+ + 3e → Crat (-) electrode; Cu+ 2e → Cu2+ at (+) electrode (b) Cr - 3e → Cr3+ at (-) electrode; Cu2+ + 2e → 2 Cu at (+) electrode Occ) cr (c) Cr + 3e → Cr3+ at (-) electrode; Cu2+ - 2e → Cu...
Given the following half reactions what is the voltage of the galvanic cell that would result from their combination [maximum positive voltage and spontaneous reaction). Show work. E° (volts) -0.74 Cr3+ (aq) + 3e Cu2+ (aq) + 2e → → Cr (8) Cu (s) +0.34 And what is the overall reaction that results after the half reactions are combined to cancel all electrons. Show work. And fill in the following abbreviated cell to represent the actual galvanic cell from above.
Given the following list of half-reaction reduction potentials, identify the reaction that will occur spontaneously as written: Half-reaction E° (V) -0.74 Cr3+ (aq) + 3 e ---> Cr (s) Sn4+ (aq) + 2 e ---> Sn2+ (aq) +0.154 -0.440 Fe2+ (aq) + 2 e ---> Fe(s) Fe3+ (aq) + e ---> Fe2+ (aq) +0.771 2 Cr (s) + 3 Fe2+ (aq) ---> 3 Fe (s) + 2 Cr3+ (aq) 2 Cr3+ (aq) + 3 Sn2+ (aq) ---> 3 Sn4+ (aq)...
a • Which of these half-cells would combine with the SHE to give the largest possible Eºcell value? • Fe3+/Fe, Ni2+/Ni, Cu2+/Cu = = = Zn2+ (aq) + 2e Cr+ (aq) + 3e Fe2+ (aq) + 2 Cd + (aq) + 2e Ni”* (aq) + 2e Sn²+ (aq) + 2e Pb2+ (aq) + 2 Fe+ (aq) + 3 2H(aq) + 2 Sn+ (aq) + 2e Cu²+ (aq) + e Cu²(aq) + 2e Zn(s) Cr(s) Fe(s) Cd(s) Ni(s) Sn(s) Pb(s) Fe(s)...
What is the value of ΔGo at 298K for the following reaction in kJ? 3A2+(aq) + 2B(s)→ 2B3+(aq) + 3A(s) A2+(aq) + 2e- → A(s) E°red = −0.188 V B3+(aq) + 3e- → B(s) E°red = − 0.750 V Thank you!!