What is the value of ΔG o in kJ at 25 oC for the reaction between the pair:
Cu(s) and Cr3+(aq) to give Cr(s) and Cu2+(aq)
Use the reduction potentials for Cr3+(aq) is -0.74 V
and for Cu2+(aq) is +0.34 V.
For these questions, I keep getting a negative answer. The
correct answer to this question is 6.3E2, and I put -6.3E2. Why is
it a positive number? Isn't the reaction spontaneous?
As reduction potential of Cu is greater than Cr ,Cu can't be oxidized by Cr.
For thess type of questions, first u decide reduction and oxidation species then after calculate E° by difference between reduction - oxidation.
Reduction at cathode and oxidation at anode.
What is the value of ΔG o in kJ at 25 oC for the reaction between...
What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Cu(s) and Cr3+(aq) to give Cr(s) and Cu2+(aq) Use the reduction potentials for Cr3+(aq) is -0.74 V and for Cu2+(aq) is +0.34 V. Give your answer using E-notation with ONE decimal place (e.g., 2.1 x 10-2 would be 2.1E-2; and 2.12 x 10-2 would also be 2.1E-2.). Do NOT include spaces, units, punctuation or anything else silly
Question 1) What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Pb(s) and Sn2+(aq) to give Sn(s) and Pb2+(aq) Use the reduction potential values for Sn2+(aq) of -0.14 V and for Pb2+(aq) of -0.13 V Question 2) What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Cr(s) and Cu2+(aq) to give Cu(s) and Cr3+(aq) Use the reduction potentials for Cr3+(aq) is -0.74 V and...
Use the standard reduction potentials from the following table to choose the weakest reducing agent among those shown below. Ag+(aq) + - + Ag(s) E° = 0.80 V Cu2+(aq) + 2e → Cu(s) E° = 0.34 V Ni2+(aq) + 2e + Ni(s) E° = -0.26 V Cr3+(aq) + 3e- → Cr(s) E° = -0.74 V Mn2+(aq) + 2e → Mn(s) E° = -1.19 V О Ni(s) Ag(s) Cr(s) Mn(s) Cu(s)
The free energy change for the following reaction at 25 °C, when [Cr3+] = 6.08×10-3 M and [Cu2+] = 1.12 M, is 67.3 kJ: Cr3+(6.08×10-3 M) + Cu+(aq) Cr2+(aq) + Cu2+(1.12 M) ΔG = 67.3 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
Given the following half reactions what is the voltage of the galvanic cell that would result from their combination [maximum positive voltage and spontaneous reaction). Show work. E° (volts) -0.74 Cr3+ (aq) + 3e Cu2+ (aq) + 2e → → Cr (8) Cu (s) +0.34 And what is the overall reaction that results after the half reactions are combined to cancel all electrons. Show work. And fill in the following abbreviated cell to represent the actual galvanic cell from above.
1) Which of the following oxidation-reduction reactions will be spontaneous in the direction written? Select all that apply. Mg2+ (aq) + Be (s) → Mg (s) + Be2+ (aq) Cu2+ (aq) + Zn (s) → Cu (s) + Zn2+ (aq) Hg2+ (aq) + Cu (s) → Hg (l) + Cu2+ (aq) Pb2+ (aq) + Cu (s) → Pb (s) + Cu2+ (aq) Fe2+ (aq) + Pb (s) → Fe (s) + Pb2+ (aq) 2) What is the value (in V)...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
Consider the balanced redox reaction below. 2Hg(I) + 2 Cu2 + (aq) +2CI-(aq)? Hg2CI2(aq) +2 Cu (s) Standard reduction Potentials are given below. Standard Reduction Potentials Reduction Half Reaction Cu2+ (aq) +2e-? Cu (s) 0.34 27 What is the cell potential, Ecell for the following concentrations at 298 K? Cu2+)-0.02M (CI1-0.3M [Hg2Cl21-0.005M Express your answer in units of Volts. 321
Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: 2Cu2+(aq) + Ni(s)2Cu+(aq) + Ni2+(aq) Answer: kJ K for this reaction would be _________ than one. Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Sn2+(aq) + Cu(s) Sn(s) + Cu2+(aq) Answer: kJ K for this reaction would be _________ than one.
Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Ca2+(aq) + 2Cut (aq) *C(s) + 2Cu2+(aq) Answer: K for this reaction would b than one. greater less Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: ca2+(aq) + 2Cu(aq)+Ca(s) + 2Cu2+(aq) kJ K for this reaction would b than one. greater Answer: less Use standard reduction potentials to calculate the standard free energy change in kJ...