I need help with this question and some concept clarifications would be great.
I need help with this question and some concept clarifications would be great. 7. (a) (2...
help me to sovle the part c clearly, I need to know bounded of that with cartesian coordinate.thanks u. A lamina in the xy - plane occupies the region that is bounded by the curves y = V1-r?, y = 19-r?, y = 13.x, and y=-x. (This means that each of the four listed curves forms a part of the boundary.) a) Sketch the region in the xy - plane. Label the boundary curves and shade the region. b) Suppose...
q5and 6 please. as much detail as possible please i need to learn how go solve these (3) Evaluate the double integral where D is the region in the lower half-plane lying between the circles 2+y2-1 and (4) Evaluate the iterated integral sinda dy. (5) In the ry-plane, let D be the region bounded by the graphs of z ty 3, 0, and 0. Find f(x,y) such that z f(x,y) defines a plane in R3 and y (6) Consider the...
(a) Evaluate the double integral 4. (sin cos y) dy dr. Hint: You may need the formula for integration by parts (b) Show that 4r+6ry>0 for all (r,y) ER-(x,y): 1S2,-2Sysi) Use a double integral to compute the volume of the solid that lies under the graph of the function 4+6ry and above the rectangle R in the ry-plane. e) Consider the integral tan(r) log a dyd. (i) Make a neat, labelled sketch of the region R in the ry-plane over...
Sketch the following region R. Then express S Sec.obda f(r,0)dA as an iterated integral over R. R The region inside the lobe of the lemniscate 2 = 5 sin 20 in the first quadrant. Sketch the region R. Choose the correct graph below. O A. OB. C. OD. Ау 4- лу 4- Ау 4- лу 4- 2 2- 2- 2- 2- o ♡ LY х х х P х 0- 04 0 0- 0 0 2 2 2. 4 o-...
I need help with this question. I do not understand the role of the plane z=x+2y since boundary of x is [0,2] and y is [0,4]. Some concept clarification would be great. 2. (5 points) Sketch (rough sketch is ok) the solid that lies between the surface z r*+1 -0, x-2. У-0, and y-4 and the plane -x+2y and is bounded by the planes x Then, find its volume. 2. (5 points) Sketch (rough sketch is ok) the solid that...
How to solve this whole question? 1 and r2 + y2 = 4 for 4. (a) Consider the region, R, bounded by the curves _ = 3c + 4y2 y 2 0. Using a double integral determine the volume under the surface and above the region R. Sketch the region of integration R. (b) Express the double integral (or integrals) that defines the area of domain of integra- tion R, where the inner integration is defined over the y-variable (c)...
[4] Sketch the region bounded above the curve of y = x2 - 6, below y = x, and above y = -x. Then express the region's area as on iterated double integral ans evaluate the integral. -4 -3 -2 -1 0 1 2 3 4 [5] Find the area of the region bounded by the given curves x - 2y + 7 = 0 and y2 -6y - x = 0.
#6 Letter C, can you please explain how you got the answer. and to check the answer key says its 1/144 Math 5C- Review 3 -Spring 19 1.) Evaluate. a) (c.) Jp z cos() dA, Dis bounded by y 0, y- 2, and 1 (d.) vd dA, D is the triangular region with vertices (0,2),(1,1), and (3,2) (a.) olr+v) dA, D is the region bounded by y and z 2.) Evaluate 3.) Evaluate J p cos(r +y)dA, where D is...
Please Answer the Following Questions (SHOW ALL WORK) 1. 2. 3. Sketch the following region R. Then express Sfer f(r,0)dA as an iterated integral over R. R The region inside the lobe of the lemniscate ? = 6 sin 20 in the first quadrant. Sketch the region R. Choose the correct graph below. OA. OB. OC. OD AY 47 AY 47 4 4- 2 2- X X 0 Sketch the region and use integration to find its area. The region...
6. (4 pts) Consider the double integral∫R(x2+y)dA=∫10∫y−y(x2+y)dxdy+∫√21∫√2−y2−√2−y2(x2+y)dxdy.(a) Sketch the region of integration R in Figure 3.(b) By completing the limits and integrand, set up (without evaluating) the integral in polar coordinates.∫R(x2+y)dA=∫∫drdθ.7. (5 pts) By completing the limits and integrand, set up (without evaluating) an iterated inte-gral which represents the volume of the ice cream cone bounded by the cone z=√x2+y2andthe hemisphere z=√8−x2−y2using(a) Cartesian coordinates.volume =∫∫∫dz dxdy.(b) polar coordinates.volume =∫∫drdθ. -1 -2 FIGURE 3. Figure for Problem 6. 6. (4 pts)...