Question

Mn(s)+NO−3(aq)→Mn2+(aq)+NO2(g) Express your answer as a ionic equation. Identify all of the phases in your answer.

Mn(s)+NO−3(aq)→Mn2+(aq)+NO2(g) Express your answer as a ionic equation. Identify all of the phases in your answer.

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Answer #1

I will assume that you are asking us to balance the complete equation, so:

First we have to add H+ at reactants and H2O at products so we can balance the Oxygen too:

Mn(s) + NO3-(aq) + H+(aq) → Mn2+ + NO2(g) + H2O(l)
Now we have to form the semireactions:

Mn goes from 0 to +2
Mn ---> Mn+2 + 2e-
N goes from +5 to +4
N+5 + 1e- ---> N+4
We must multiply this semireaction by 2 to balance the electrons
2N+5 + 2e- ---> 2N+4
Now we distribute these new coefficients back into the equation
Mn(s) + 2NO3-(aq) + H+(aq) → Mn2+ + 2NO2(g) + H2O(l)
Now we balance the spectators:
There are 6 osygens on reactants so we must add one on the products by changing H2O to 2H2O to get 6
The Nitrogens are already balanced
Mn(s) + 2NO3-(aq) + H+(aq) → Mn2+ + 2NO2(g) + 2H2O(l)
there are 4 Hydrogens on products so we need 4 on reactants
Mn(s) + 2NO3-(aq) + 4H+(aq) → Mn2+ + 2NO2(g) + 2H2O(l)
Now the electrons, atoms and charges are balanced

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