Question

1. A proton is moving at an angle of 80° to a uniform magnetic field. What is the relationship between the direction of the force on the proton and the direction of the magnetic field? * (1 Point) parallel to the magnetic field at an angle of 10° to the magnetic field at an angle of 80° to the magnetic field at an angle of 180° to the magnetic field perpendicular to the magnetic field

Answer 1

colith velocity (1.) magnetic force on a moving charge a en magnetic field Be is 8 = a (x8 | so, magnetic force is always perpendicular to both velocity and magnetic field. Force on proston is perpendicular to magnet -ic field. 2.) Force on electron is &=-eluxe 1800 IFTE selule senise =0 force on electron is zero. current carying loop of tic moment i en magnetic field B is: 2 = û xg 171 = lū118] semo - Torque is maximum when angle between Satin madh is o=90 <3-> Torque on open magne- CS

(4.) when velocity X sje 'F FE f X A x x is o=180° of charge is perpendicular , to Magnetic field B; then, magnetic force is perpendicular to velocity and remains in same *B plane always. So, peoth of charge is sekerler circular. <s.) when is opposite to B 9D1800 then angle between and B B i force is f= quB sin 188% =0 =0 >=0 Criven statement is true. <-> Cutting a bar magnet however small, there will be always a north pale and south pole of same strength. So, given statement is false of magnetic force on current how element Ide? in magnetic & field Š is df = R&T XR = I ld 1181 sino CS Scanse de Cancha Tom

mague I di :. If O=0° then, sino=simo=0 -: LdF ! Co for 0909. So, when current is parallel to the field lines then ctic force on the were es zero. 8.3 d = 1 de x B² 1 de l=1/dil 1871 sino lat is more moun when sino=1 » o=goo. statement is true <9.5 An electroc current produces a magnetic field. since a current carrying were is overall neutral so it does not produce electric cs field itenteill current varries with time So, given CamScanner