The number of days a student is absent in a four week period is
recorded along with the test score over the material covered over
those four weeks. Consider the output from Excel of a linear
regression:
Claim: There is a linear correlation between the number of days
missed and the test score over the material covered.
Regression Statistics
Multiple R | .699389593 |
R squared | .489145802 |
Adjusted R Square | .446574619 |
Standard error | 14.49517418 |
error observations | 14 |
Anova
df | ss | ms | f | |
Regression | 1 | 2414.179 | 2414.179 | 11.49007 |
residual | 12 | 2521.321 | 210.1101 | |
total | 13 | 4935.5 |
Coefficients | Standard Error | t Stat | P-value | |
Intercept Classes | 82.30589096 | 5.209439 | 15.79938 | 2.14E-09 |
missed | -3.51664837 | 1.03751 | -3.3897 | .005371 |
What is the correlation coefficient, p value, and degrees of freedom?
The number of days a student is absent in a four week period is recorded along...
5- Interpret the coefficient of determination (R-squared) and the F test. SUMMARY OUTPUT Regression Statistics Multiple R 0.8811 R Square 0.7764 Adjusted R Square 0.7205 Standard Error 14.7724 Observations 16 ANOVA df SS MS F Regression 3 9091.7392 3030.5797 13.8874 Residual 12 2618.7008 218.2251 Total 15 11710.44 Coefficients Standard Error t Stat P-value Intercept 29.1385 174.7427 0.1668 0.8703 PFH -2.1236 0.3405 -6.2361 0.0000 PR 1.0345 0.4667 2.2164 0.0467 M 3.0871 0.9993 3.0892 0.0094
Consider the simple linear regression model: HARD1 = β0 + β1*SCORE + є, where є ~ N(0, σ). Note: HARD1 is the Rockwell hardness of 1% copper alloys and SCORE is the abrasion loss score. Assume all regression model assumptions hold. The following incomplete output was obtained from Excel. Consider also that the mean of x is 81.467 and SXX is 81.733. SUMMARY OUTPUT Regression Statistics Multiple R R Square Adjusted R Square 0.450969 Standard Error Observations 15 ANOVA df...
A new fad diet called Trim-to-the-MAX is running some tests that they can use in advertisements. They sample 25 of their users and record the number of days each has been on the diet along with how much weight they have lost in pounds. The data are below. Days on Diet Weight Lost Regression Statistics Multiple R 0.9851 R Square 0.9705 Adjusted R Square 0.9668 Standard Error 1.9173 Observations ANOVA SS MS Significance F Regression 967.0912 967.0912 263.0757 2.09917E-07 Residual...
Based on the below data what will be the value of multiple R? Regression Statistics Multiple R R Square Adjusted R Square Standard Error Observations 8 ANOVA df SS MS F Regression 1 29 29 7 Residual 6 26 4 Total 7 Coefficients Standard Error t Stat P-value Intercept 1 31.274666 3.984284 0.007248 Advertising (thousands of S) 42 6.19330674 1.610802 0.158349 Submit Answer format: Number Round to: 2 decimal places.
(13 points) Suppose you have a simple linear regression model such that Y; = Bo + B18: +€4 with and N(0,0%) Call: 1m (formula - y - x) Formula: F=MSR/MSE, R2 = SSR/SSTO ANOVA decomposition: SSTOSSE + SSR Residuals: Min 1Q Modian -2.16313 -0.64507 -0.06586 Max 30 0.62479 3.00517 Coefficients: Estimate Std. Error t value Pr(> It) (Intercept) 8.00967 0.36529 21.93 -0.62009 0.04245 -14.61 <2e-16 ... <2e-16 .. Signif. codes: ****' 0.001 '** 0.01 '* 0.05 0.1'' 1 Residual standard...
Following a regression analysis output : SUMMARY OUTPUT Regression Statistics Multiple R 0.719422 R Square Adjusted R Square 0.477366 Standard Error Observations 14 ANOVA df SS MS F Regression 1 3.028885709 Residual 12 2.823257148 Total 13 5.852142857 Coefficients Standard Error t Stat P-value Intercept 1.157091 0.566482479 0.063699302 Satisfaction with Speed of Execution 0.636798 0.177478218 0.003726861 Group of answer choices R Square is 0.517 Standard error is 0.386 Residuals are 2.823 F-test is 11.87 R Square is 0.517 Standard error is...
A regression model relating x, number of salespersons at a branch office, to y, annual sales at the office (in thousands of dollars) provided the following computer output from a regression analysis of the data. Where n total=26. a. Write the estimated regression equation (to whole number). y=_____+_____x b. Compute the F statistic and test the significance of the relationship at a .05 level of significance. (to 2 decimals) F-value ____ p-value is _______, we _________ h0 c. Compute the...
theres 4 total questions oare Was teR Mailed to these tive cardhoiders requesting intormation on the numbe time period. The data follow. Sick Days & Age iles 1,000's)K$1,000's) harges Cardholder 1.2 2.0 1.5 2.3 2.7 1.6 2.5 2.2 4.2 3.2 2.7 0.5 2.1 0.8 reA regression Analysis has been performed to estimate the model and the output is given. Regression Statistics Multiple R R Square Adjusted R Square ,19954 56026 0.31389 71405 tandard Error bservations ANOVA O 2019 01:41:34 A...
SUMMARY OUTPUT Regression Statistics Multiple R 0.99806038 R Square 0.996124522 Adjusted R Square 0.995155653 Standard Error 387.1597665 Observations 16 ANOVA df SS MS F Significance F Regression 3 4.62E+08 1.54E+08 1028.131 9.91937E-15 Residual 12 1798712 149892.7 Total 15 4.64E+08 Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0% Intercept 1946.802039 504.1819 3.861309 0.002263 848.2839829 3045.32 848.284 3045.32 XRay (x1) 0.038577091 0.013042 2.957935 0.011966 0.010161233 0.066993 0.010161 0.066993 BedDays (x2) 1.039391967 0.067556 15.38573 2.91E-09 0.892201042 1.186583...
You were asked by your manager to evaluate the regression tables below to decide which cost driver would be best to use for the production department. Since your manager is new and does not understand the regression analysis tables, you will need to explain why one set of statistics is better than the other and why you have chosen the better driver. Manufacturing Direct Labor Hours Regression Statistics Multiple R 0.799304258 R Square 0.638887297 Adjusted R Square 0.602776026 Standard Error...