D Question 29 1 pts Solve: 22-3-7 x2 X-5 None of these X=5 x=2 X-2 x...

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29 - 12x-31 = 7 case I if k23 124-3) = 2K-3 2x-3= 7 2X10 k=5 Case II if KL3 then 12x-3) = -(24-3) - (2x-3) = 7 2k-3 =-7 2 re= G 30) -4+134+5) 25 13x + 5) 29 K2-5 then 13r451 = 34ts w? 12 3x+ 59 3R ²4 x? // Case ]I by K2-5 then 13K+5) = -(36+5) - (3k+

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