Question

We launch, to the left, at 15 m / s, a mass of 2 kg, attached to a spring whose elastic constant is 98N / m. The mass is launched from the position xo = + 3m (i.e. three meters to the right of its equilibrium position).

a. What will be the oscillation period?
b. Where will the mass be three seconds later?
c. When will the mass be 50 cm to the left of its initial position for the second time?

Answer 1

Soin k=98 N/m 0 = 15 ml mm 24 1x = A sinut +6) where A = amplitude 3= frequency. 3m w (equilibrium bositor) (9) T = 271 min 2 98 2 T 210.9 sec 7 Aro Jet time t at Jaunch position. x= A sin (wt +) W = 2 TT 21-7 ot =0) 3 m 3 = A sino dx J! = 15 ml 5 Aw cos a = v= 15mis 2 A cas4 = 15/7 from eah 8 = {135 + 2 A=15.15 0 = tan- 1 ( 22 ) = 54,46 (phoge angle). X = 15.15 sin (7t + 54.46) at t = 380 position 22 15:15 sin ( 7x3 +54.46) = 14.664 from equillitorium position soom left means x=23-0.5m) but in 0,5) = 15.15 sin (7+ + 54.46) (time is not in negah 6.42 3 Seel App * = -6.423 Scanned with CamScanner