Question

4. The Gaussian surface is a sphere with a radius of 10 cm. At the center of the sphere is a point charge, At the Gaussian surface (10 cm from the point charge) an electric field of 5000 N/C is directed away from the point charge.

Answer 1

solution & radius r= 10 cm E = 5000 N/C loom Gaussian Surface ® Gaurs law : charge enclosed by the flux passing through the Caussian' surface surface 0 - Genclave *+-fēdis O E-ds = qene s l angle between Ē and als u o į Eds. Cezo° = Lene Eģds = qene T): loom E. U772 = qene Jene - E | 47€0) x2 = 5000 x L x (o xrőmy? -6 2 -4 Genc = 5 x 10 x 10 X 10' =.55555 X108 - 9x109 9 Ime = 5.5568107C

© charge Genclosed by the surface - 5.556 X10 ac -5.556 ne @ formula for the electric field for the point charge as a function of r. Ez L. Lene în radially outwald direction 4A r r=c0cm E = 9x109 x 5.5564100 1 [loxioaja E = 50.004 X10 Ē = 5000.4 û NIC 2 A Е. Бсто пw/с electric field î shows that the direction of is radially outward.