? with Given radio of the optical cavity consisting of two mirrors curvature R=1 m separated by doo.5m. Unitcell NO fig-1 optical cavity. M We know that an optical cavity of of curvature of the mirror rere length L and radio is stable when
os (1-21) (1-1/R2) <t Here Läd=0. 5m and Ri= R2 = 1 m .. Hence, (1-4) (1-1/+2) = (1-0.5) (1-05) Ĉ 0.5*0.5 = 0.25 Hence the cavity is stable. (6) We know that minimum beam waist where wo²= dd {9,92 (1-9192) (l/ 9, +92-29192)2 S i gi-(1-d6e, , 92=(1-4ks) giz (1-05) 922 (1-os) gia 0.5 g =0.5 nmn n A A A for a= 632 nm = 632 x 10 m. we have wo2 o.sx 632810 9 qosxois (in oisxos) (% I Cosmo15 2x0.5x0512 0.5 X 632 s o.1875 0:25 wo z 2.9514810-4 n. Hence spot m size awo = 5.90 28x10 = 0.59 mm. A Hence spot size at the middle for t= 632 nm is 0.159 mn
21 trip time, (a) We know the round TRT= 22 length between the two mirror Where L= e = speed Optical path of light. Here the optical path length Land. ace, Teta and e. Hence, - Round trip time TRTE In the separation fabry Perot transmission spectrum the between two peaks AXpeak tom, sp And corresponding FWHM, ATF WHM = 0.03 nm FWHM= full width at half maximum, We know Are and • Now, we can Hey야 들리지 Hences e os en on 22 2 - Hence da at In 2mA 2nd
(e) Now photon life time, Ta and 2nd