Question

[4] 8 points (2 points for each part) use file Mystery.txt

For each call below to the mystery method, write the output that is produced, as it would appear on the console:

public static void mystery (int x, int y)

{

int s = 0;

while (x > 0 && 2 * y >= x)

{

System.out.print(s + " ");

y = y - x;

x--;

s = s + x;

}

System.out.println (s);

}

A. mystery (-2, -6);

B. mystery (2, 3);

C. mystery (4, 8);

D. mystery (10, 31);

Answer 1

Below are your answers: -

a)

0

Explanation: - x is -2 so while loop doesnt have any iteration as x is less than 0.

b)

0 1 1

Explanation: -

x = 2, y = 3, while condition is true, so it prints 0 and after iteration x = 1, y = 1, s = 1

in second iteration , while condition is again true, so it prints 1 and after iteration, x = 0, y = 0 , s = 1

There is no third iteration because x is equal to 0, and last statement prints 1 again.

c)

0 3 5 6

Explanation: -

x = 4, y = 8, while condition is true, so it prints 0 and after iteration x = 3, y = 4, s = 3

in second iteration , while condition is again true, so it prints 3 and after iteration, x = 2, y = 1 , s = 5

in third iteration , while condition is again true, so it prints 5 and after iteration, x = 1, y = -1 , s = 6

There is no third iteration because y is negative, and last statement prints 6

d)

0 9 17 24 30

Explanation: -

The flow is as per previous parts.