Question

please help asap!! i dont know how to do the graphs

Graphical Determination of Rate Plot a graph (excel or sheets) of Total moles of SO consumed ("Y") vs. time ("x") for EACH solution. The slope of the line (A [3,0,?] /At) is the "rate" of each reaction. Submit a graph for each reaction with your post lab report 1. Rate of each solution: Solution 1 Solution 2 Solution 3 Solution 4

Answer 1

Rate of reaction for

Solution 1: 9.726E-07

Solution 2: 2.040E-06

Solution 3: 1.400E-06

Solution 4: 9.646E-07

For solution. 1:

Solution 1 Initial (S208-) = 0.05M Remaining Molarity = Initial - consumed Cumulative time (s) 0 185 372 547 748 996 1209 1433 [S208 -] consumed (M) 0.00E+00 2.00E-04 4.00E-04 6.00E-04 8.00E-04 1.00E-03 1.20E-03 1.40E-03 Slope R2 = Molarity in M of remaining S208-- 5.00E-02 4.98E-02 4.96E-02 4.94E-02 4.92E-02 4.90E-02 4.88E-02 4.86E-02 -9.726E-07 0.9971 Molarity of S208-- vs Time 5.02E-02 5.00E-02 4.98E-02 4.96E-02 4.94E-02 [S208--] 4.92E-02 4.90E-02 4.88E-02 4.86E-02 4.84E-02 0 200 Time (s) 400 600 800 1000 1200 1400 1600

Rate of reaction = -(slope) = - (-9.726E-07) = 9.726E-07

= = = = = = = = = = = = =

For solution 2

Solution 2 Initial (S208--] = 0.10M Remaining Molarity = Initial - consumed Cumulative time (s) 0 Molarity in M of remaining S208- 1.00E-01 91 186 283 [S208 --] consumed (M) 0.00E+00 2.00E-04 4.00E-04 6.00E-04 8.00E-04 1.00E-03 1.20E-03 1.40E-03 Slope R2 = 9.98E-02 9.96E-02 9.94E-02 9.92E-02 9.90E-02 9.88E-02 387 482 582 684 9.86E-02 -2.040E-06 0.9998 Molarity of S208-- vs Time 1.00E-01 1.00E-01 9.98E-02 9.96E-02 [S208--] 9.94E-02 9.92E-02 9.90E-02 9.88E-02 9.86E-02 9.84E-02 0 100 Time (s) 200 300 400 500 600 700 800

Rate of reaction = - (slope) = -(-2.040E-06) = 2.040E-06

= = = = = = = = = = = = = =

Solution 3.

Rate of reaction = -(slope) = -(-1.400E-06) = 1.400E-06

Solution 3 Initial (S208--] = 0.05M Remaining Molarity = Initial - consumed Cumulative time (s) 0 [S208 --] consumed (M) Molarity in M of remaining S208-- 0.00E+00 5.00E-021 122 2.00E-04 4.98E-02 298 4.00E-04 4.96E-021 384 6.00E-04 4.94E-021 527 8.00E-04 4.92E-02 680 1.00E-03 4.90E-02 840 1.20E-03 4.88E-02 1010 1.40E-03 Slope = R2 = 4.86E-02 -1.400E-06 0.9957 Molarity of S208-- vs Time 5.02E-02 5.00E-02 4.98E-02 4.96E-02 [S208-) 4.94E-02 4.92E-02 4.90E-02 4.88E-02 4.86E-02 4.84E-02 0 200 Time (s) 400 600 800 1000 1200

= = = = = = = = = = = = = = = = = = =

Solution 4.

Solution 4 Initial (S208--] = 0.1M Remaining Molarity = Initial - consumed Cumulative time (s) 0 192 390 593 [S208 --] consumed (M) 0.00E+00 2.00E-04 4.00E-04 6.00E-04 8.00E-04 1.00E-03 1.20E-03 1.40E-03 Slope R2 = Molarity in M of remaining S208-- 1.00E-01 9.98E-02 9.96E-02 9.94E-02 9.92E-02 9.90E-021 9.88E-021 9.86E-02 -9.646E-07 0.9995 802 1011 1229 1450 Molarity of S208-- vs Time 1.00E-01 1.00E-01 9.98E-02 9.96E-02 9.94E-02 (S208- 9.92E-02 9.90E-02 9.88E-02 9.86E-02 9.84E-02 400 600 800 1000 1200 1400 1600 0 200 Time (s)

Rate of reaction = -(slope) = -(-9.646E-07)

= 9.646E-07