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56)Consider a random sample of n 80 and S62.35. Find the level of confidence (1- a% if the maximum error is less than 1 B) 7.
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Answer #1

here error =t*standard deviation/sqrt(n)

therefore ; critical t =10*sqrt(80)/62.35 =1.435

for above test statistic at (n-1=79) degree of freedom; level of confidence =84.72%

option D is correct

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