Recall the formula for a proportion confidence interval is
p^?zp^(1?p^)n?????????<p<p^+zp^(1?p^)n?????????
Thus, the margin of error is E=zp^(1?p^)n????????? .
NOTE: the margin of error can be recovered after constructing a confidence interval on the calculator using algebra (that is, subtracting p^ from the right endpoint.)
In a simple random sample of size 59, taken from a population, 20 of the individuals met a specified criteria.
a) What is the margin of error for a 90% confidence interval for p, the population proportion?
b) What is the margin of error for a 95% confidence interval for p?
NOTE: These margin of errors are greater than .10 or 10%.
c) How big of a sample is needed to be certain that we have a margin of error less than .10 (or 10%) at 90% confidence?
d) How big of a sample is needed to be certain that we have a margin of error less than .10 (or 10%) at 95% confidence?
Recall the formula for a proportion confidence interval is p^?zp^(1?p^)n?????????<p<p^+zp^(1?p^)n????????? Thus, the margin of error is...
הסט Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.35 and n 120 Nama 90% c.99% Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table Due: Curre Atter Late The margin of enor for a confidence interval to o und to three decimal places as needed) imate the population proportion for the confidence levels
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p , the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for the proportion of the population in Category A given that 18% of a sample of 450 are in Category A. Round your answer for the point estimate to two decimal places, and your...
Question Help 8.4.3 Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.38 and n 100. a, 90% b. 95% c.98% Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table a. The margin of error for a confidence interval to estimate the population proportion for the 90% confidence level is Round to three decimal places as...
DOH Determine the margin of error for a 90% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 for the following sample sizes. an 100 bin 200 cn=260 Nam Due Click the icon to view a portion of the Qurtulative Probabilities for the Standard Normal Distribution table. Currea. The main forror for a 90% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 and sample siren 100 is (Round to...
To calculate a confidence interval, the margin of error (E) must first be calculated. The Margin of Error, E, for means is: E = 1.96*s/sqrt(n), where s is the sample standard deviation, n is the sample size. The “sqrt” stands for square root. The Margin of Error, E, for proportions is: E = 1.96*sqrt[p*(1-p)/n], where s is the sample standard deviation, n is the sample size, and p is the proportion. Use the Confidence Interval formula above, and the correct...
Determine the sample size needed in forming a 95% confidence interval for a proportion with margin of error of 0.04. (Use the “safe approach” for the population proportion (i.e., p=.50) Repeat part a.) for a margin of error of 0.02.
sample should be taken to provide a 95% confidence interval with a margin of error of .05? At 95% confidence, how large a sample should be taken to obtain a margin of error of .03 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p* 34.
Determine the margin of error for a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 for the following sample sizes. a. nequals100 b. nequals180 c. nequals260 LOADING... Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table. a. The margin of error for a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 and sample size nequals100 is nothing.
Determine the margin of error for a confidence interval to estimate the population mean with n=25 and s =1.6 for the confidence levels below. a) 80% b) 90% c) 99% a) The margin of error for an 80% confidence interval is. (Round to two decimal places as needed.) b) The margin of error for a 90% confidence interval is. (Round to two decimal places as needed.) c) The margin of error for a 99% confidence interval is. (Round to two...
Determine the sample sizen needed to construct a 95% confidence interval to estimate the population proportion for the following sample proportions when the margin of error equals 5% . a.p 0.70 b. p 0 80 c.p 0 90 Click the icon to view a table of standard normal cumulative probabilties a, nm (Round up to the nearest integer) Determine the sample sizen needed to construct a 95% confidence interval to estimate the population proportion for the following sample proportions when...