1. A 25 kg child runs at a speed of 5.0 m/s and jumps onto a stationary...
1. A 25 kg child runs at a speed of 5.0 m/s and jumps
onto a stationary shopping cart and holds on for dear life. The
cart has mass 12 kg. Assuming the child rides on the cart after the
collision, find the speed of the child and shopping cart just after
the child jumps on. Show all work please
Homework Answers
Request Answer!
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
Add Answer to:
1. A 25 kg child runs at a speed of 5.0 m/s and jumps
onto a stationary...
9. A child of mas 40kg runs at a speed of 5 m/s and jumps onto...
9. A child of mas 40kg runs at a speed of 5 m/s and jumps onto a disc shaped merry go round of mass 100 kg and radius 5m. The child lands on the outer edge of the disc when the disc is stationary.. What is the angular speed of the merry go round with the child on it? Was energy lost? If so, how much energy was lost in the process? loo kg 5 he
A child runs and jumps into an)initially stationary) playground swing. The child is moving in 5.0...
A child runs and jumps into an)initially stationary) playground swing. The child is moving in 5.0 m/s just before landing in the seat of the swing. Her mass is 20 kg, the swing seat has mass 5.0 kg, and the ropes holding it have negligible mass. How high does the swing rise from its initial position? 8.0 m 1.0 m 1.3 m 1.7 m 0.82 m A spring is compressed from its relaxed position by an amount of 0.20 m....
An 85.0 kg child runs in a straight line towards the edge of a stationary merry-go-round...
An 85.0 kg child runs in a straight line towards the edge of a stationary merry-go-round at 2.50 m/s. The merry-go-round is in the shape of a disk and has a diameter of 4.50 m and a mass of 235 kg. The child jumps onto and stays on the merry-go- round. What is the angular momentum of the child before this collision, in kg m2/s? (A) What is the moment of inertia of the merry-go-round, in kg m27 [B) What...
A 40.0-kg child running at 3.00 m/s suddenly jumps onto a stationary playground merry-go-round at a...
A 40.0-kg child running at 3.00 m/s suddenly jumps onto a stationary playground merry-go-round at a distance 1.50 m from the axis of rotation of the merry-go-round. The child is traveling tangential to the edge of the merry-go-round just before jumping on. The moment of inertia about its axis of rotation is 600 kg ? m2 and very little friction at its rotation axis. What is the angular speed of the merry-go-round just after the child has jumped onto it?...
A 36.0 kg child runs with a speed of 2.80 m/s tangential to the rim of...
A 36.0 kg child runs with a speed of 2.80 m/s tangential to the rim of a stationary merry-go-round(Figure 1) . The merry-go-round has a moment of inertia of 518 kg⋅m2 and a radius of 2.31 m . When the child jumps onto the merry-go-round, the entire system begins to rotate. Calculate the final kinetic energy of the system.
A 65 kg skater runs at 5 m/s and jumps onto his 2.5 kg skateboard which...
A 65 kg skater runs at 5 m/s and jumps onto his 2.5 kg skateboard which was initially stationary. What is the velocity of the skater and the board after he lands?
A 46.7 kg student runs down the sidewalk and jumps with a horizontal speed of 4.10...
A 46.7 kg student runs down the sidewalk and jumps with a horizontal speed of 4.10 m/s onto a stationary skateboard. The student and skateboard move down the sidewalk with a speed of 3.86 m/s. a) Find the mass of the skateboard. Answer in units of kg b) How fast would the student have to jump to have a final speed of 6.54 m/s? Answer in units of m/s..
A 25-kg child running at 1.6 m/s jumps onto the outer edge of a merry-go-round of...
A 25-kg child running at 1.6 m/s jumps onto the outer edge of a merry-go-round of 200-kg mass and 1.8 m radius. If the merry-go-round starts from rest, what is the final angular velocity in rad/s of the child and merry-go-round? Use conservation of angular momentum and treat the merry-go-round as a solid disk.
A 5 kg cart rolling to the right at 7 m/s runs into a 7 kg...
A 5 kg cart rolling to the right at 7 m/s runs into a 7 kg cart rolling to the left. After the collision, both carts are stationary. Part A What was the original speed of the 7 kg cart?
Page 13 9. A 49.8-kg athlete running at 4.54 m/s suddenly jumps onto a stationary playground...
Page 13 9. A 49.8-kg athlete running at 4.54 m/s suddenly jumps onto a stationary playground merry-go-round at a distance 1.45 m from the axis of rotation of the merry-go-round. She is traveling tangential to the edge of the merry-go-round just before jumping on. The moment of inertia about its axis of rotation is 625 kg m2 and very little friction at its rotation axis. What is the angular speed of the merry-go-round just after she has jumped onto it?...
9. A child of mas 40kg runs at a speed of 5 m/s and jumps onto a disc shaped merry go round of mass 100 kg and radius 5m. The child lands on the outer edge of the disc when the disc is stationary.. What is the angular speed of the merry go round with the child on it? Was energy lost? If so, how much energy was lost in the process? loo kg 5 he
A child runs and jumps into an)initially stationary) playground swing. The child is moving in 5.0 m/s just before landing in the seat of the swing. Her mass is 20 kg, the swing seat has mass 5.0 kg, and the ropes holding it have negligible mass. How high does the swing rise from its initial position? 8.0 m 1.0 m 1.3 m 1.7 m 0.82 m A spring is compressed from its relaxed position by an amount of 0.20 m....
An 85.0 kg child runs in a straight line towards the edge of a stationary merry-go-round at 2.50 m/s. The merry-go-round is in the shape of a disk and has a diameter of 4.50 m and a mass of 235 kg. The child jumps onto and stays on the merry-go- round. What is the angular momentum of the child before this collision, in kg m2/s? (A) What is the moment of inertia of the merry-go-round, in kg m27 [B) What...
Page 13 9. A 49.8-kg athlete running at 4.54 m/s suddenly jumps onto a stationary playground merry-go-round at a distance 1.45 m from the axis of rotation of the merry-go-round. She is traveling tangential to the edge of the merry-go-round just before jumping on. The moment of inertia about its axis of rotation is 625 kg m2 and very little friction at its rotation axis. What is the angular speed of the merry-go-round just after she has jumped onto it?...
Most questions answered within 3 hours.
-
lease solve all the
questions, don't need to explanations
Q1 - All animal
species have general...
asked 46 minutes ago -
Business Phasing
1.Discuss the logical progression for growing a business, which
starts from the initial idea...
asked 51 minutes ago -
Modify
When executing on the command line having only
this program name, the program will accept...
asked 2 hours ago -
Kenny Electric Company's noncallable bonds were issued several
years ago and now have 20 years to...
asked 2 hours ago -
find H(e^Jtheta) at theta= 0, pi/10, pi/20, pi/2 for
the following:
a) H(e^Jtheta)= 1+e^Jtheta
b) H(e^Jtheta)=...
asked 2 hours ago -
Home Corporation will open a new store on January 1. Based on
experience from its other...
asked 3 hours ago -
In a neoclassical model, use the IS-LM to analyze the effect of
a permanent money supply...
asked 3 hours ago -
An electron passes through a point 2.67 cm from a long straight
wire as it moves...
asked 4 hours ago -
A grammar is a 4-tuple G, G = (Ν, Σ, Π, Σ, S) where, Ν is...
asked 5 hours ago -
In this part, calculate the present values. Use the Excel PV
function to compute the present...
asked 4 hours ago -
Part 1. Primitive Types, Sorting, Recursion for
Homework.java
a) Implement the static method initializeArray that receives...
asked 6 hours ago -
Using C++, build a sorter that can rank a sequence of numbers in
a descending order....
asked 6 hours ago