Question

What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cl2 pressure is 1.05x10-4 atm, the CT concentration is 1.19M, and the Fe2+ concentration is 1.17M ? Cl2(g) + Fe(s) >2CI+ (aq) + Fe2+(aq) Answer: v The cell reaction as written above is spontaneous for the concentrations given V - true false Submit Answer Retry Entire Group 9 more group attempts remaining

Answer 1

+ Cl2 (g) + Fe(s) - 200- + fe 24 car.) clance = 1.36v tre etife = -0.440 Ecell = Ecathode - Eanode. 1.36V - (-0.440) = 1.8V using neaust egn. Ecell = Ecell - 0.05al log (Pl) = 1.8v - 0.0591 v 2 = 1.84 -0.1240 = log (1.17m) (1.19 m 2 (1.05 X10-4) 1.66 v. Ecell = + 1.66 V spontane ous = Thue = 2H+ (aq) + mncs) - H₂ (9) + muht car. EM+/14 = 0 Emn2tlmna - 1.180 V tcell - Ecathode tanode = o- (-1.182v) = 1.182v Ecell = 1.182v- ooosal log r[mn2+ ] [PH] I (H+]2 1.182 V- Dooşal log/(5. 54 x10-Y) (9.48X1024) (1039m 12 = 1.182v + o. 164 v - 1.350 Ecole = + 1.35V = spontane ous True