Two point charges each of 1.0 μC are placed at the positions (–1 m, 0) and (1 m, 0) respectively. What is the electric field at the point (0, 1 m)?
Full explanation and solution please! I dont understand how symmetry works along the x-axis and what is cancelled out.
charge 1 uC is placed at A(-1, 0) and B(1,0) .
and field due charge Q at distance r , E = kQ/r^2
and away from charge if Q is +ve.
at point P:
due to charge at A, AP = sqrt(1^2 + 1^2) = 1.414 m
and direction of AP = tan^-1((1-0)/(0-(1))) = 45 deg
E1 = [(9 x 10^9 x 1. x 10^-6)/(1.414)^2] (cos45i + sin45j)
E1 = 3181.98i + 3181.98j N/C
due to charge at B, BP = sqrt(1^2 + 1^2) = 1.414 m
and direction of BP = tan^-1((1-0)/(0-(-1))) = 180-45 = 135 deg
E2 = [(9 x 10^9 x 1. x 10^-6)/(1.414)^2] (cos(135)i + sin(135)j)
E2 = - 3181.98i + 3181.98j N/C
Enet = E1 + E2 = 6363.96 N/C j
field is 6363.96 N/C along +ve y axis.
Two point charges each of 1.0 μC are placed at the positions (–1 m, 0) and...
Point charges 4.5 μC and -2.3 μC are placed on the x axis at (12 m , 0) and (-12 m , 0), respectively. Find the point to the left of the negative charge where the electric potential vanishes. Is the electric field at the point found in part A positive, negative, or zero?
6) Two point charges q1 = 4.0 μC and q2 = -8.0 μC are placed along the x-axis at x1 = 0 m and x2 =0.20 m, respectively. What is the electric potential energy of this system of charges? 7) Gauss's law can be applied using any surface. True/ false?
Point charges 3.5 μC and -2.4 μC are placed on the x axis at (11 m , 0) and (-11 m , 0), respectively Find the point to the left of the negative charge where the electric potential vanishes. X=
Point charges of 26.0 μC and 41.0 μC are placed 0.500 m apart. (a) At what point along the line connecting them is the electric field zero? (b) What is the magnitude and direction of the electric field halfway between them?
A dipole is formed by point charges +3.8 μC and -3.8 μC placed on the x axis at (0.30 m , 0) and (-0.30 m , 0), respectively. Part A At what positions on the x axis does the potential have the value 7.6×105 V ? Express your answers using two significant figures separated by a comma. Please show step by step the calculations. Thank you so much x1 x2
Two point charges, Q1 = 3.2 μC and Q2 = -1.3 μC , are placed on the x axis. Suppose that Q2 is placed at the origin, and Q1 is placed at the coordinate x1 = − 6.0 cm. At what point(s) along the x axis is the electric field zero? Determine the x-coordinate(s) of the point(s). At what point(s) along the x axis is the potential zero? Determine the x-coordinate(s) of the point(s). At what point(s) along the xx...
Question : IP Point charges 3.5 μC and -2.1 μC are placed on the x axis at (16 m , 0) and (-16 m , 0), respectively. Ive looked at other questions that are very similiar but the E0 is very confusing for me. How do i put it in my calculator or can you explain the math step by step? Problem 20.32 Part A Constants| Periodic Table Find the point to the left of the negative charge where the...
IP Point charges 4.4 μC and -2.4 μC are placed on the x axis at (15 m , 0) and (-15 m , 0), respectively. Find the point to the left of the negative charge where the electric potential vanishes.
wo charges, -2.1 μC and -4.7 μC , are located at (-0.60 m , 0) and (0.60 m , 0), respectively. There is a point on the x-axis between the two charges where the electric field is zero. Find the location of the point where the electric field is zero.
A point charge of 30 μC is placed at the origin and another point charge of 55 μC is placed at x=0.8 m as shown. a) At what point along the x axis is the electric field zero? b) What is the x component of the electric field halfway between the charges?