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Problem 5. Ct.99% for protozoan inactivation by hypochlorous acid (HOCI) at pH = 7 and T = 5°C is 100 mg.min/L. a. What is Ct
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Answer #1

1. Ct = Dh ÷ t

Where Dh = Disinfection hurdle.

t=time

From the given value of Ct=100 and t=5 we can calculate Dh, which is 500.

As pH remains same

Calculating Ct at 9°C

Ct= Dh÷t

Ct = 500÷7

Ct= 71.4

Calculating Ct at 16° C

Dh= 500

Ct= 500÷16

31.25

3. 3-log inactivation of viruses refers to 99.9%0removal.

1-log =90% removal

2-log=99% removal

3-log=99.9% removal

4-log=99.99% removal

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