Question

draw a free body diagram, explain why the forces of friction are in the directions drawn, a derive an equation of motion for mass A and mass B, in terms of acceleration and Tension (T)

Exercise C. A pulley problem (10 points) In this problem we are interested in the pulley-mass system shown in Error! Reference source not found. Treat both mass A and mass B as particles. ma = 1300 kg mg = 400 kg HA=0.06 HB = 0.13 Figure 1 1. Draw individual free body diagram for mass A and mass B. • Ensure you identify the correct direction of the friction forces. Logically justify your selected friction direction (1 sentence with some supporting calculations), Answer within the space provided by this box; the box can be expanded if needed

Answer 1

Block A 1300x9&IN 22T --> Block A move downwards and prichonal Proce acts opposite b disechon of mohon. F=HANR 5300 E Fy - Maly (n =) Ne = 1300x9184 x W330 NR = 1104-4.42N E Fx = MAGxKt) 1300x9.81 $30°-2T - MANR = 1300AA 1300x9.5151 3 0 - 2T-0.06 (11044-42) = 130000 5713.83 - 27 = 1300 AA — D 400X9.81 N Block B Block B moving upwards otherad frece acting down words, Ery = mbay to NR = 400x9.6150 NR = 681-395

EF=G (+) MBNR-T + 400x9.81 oslo = 400 AB 0.13 x 681.39-T + 400.9.811810 = 400 Az 3952.96-T = 400am - @ QA = -293 sub in 5713.83-2T = -1300 X 298 5713.83–27 =-2600 AB - solving and ② T=3695.06N ③ AB=0.6447 m/s² a = – 1.3294m/52