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Problem 5.3-1 5 Ohms 20 Ohms o20 Ohms 2 The inputs to this circuit are the voltage source voltages v1 and v2. The output of t

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Answer #1

By using superposition principle:

Let V1 only active and V2 is open then,

V01 = (V1*20)/25

=0.8V1.

Now,let V2 only active V1 is open then,

V02 = (V2*20)/(20+20)

= 0.5 V2

According to superposition principle,

V0 = V01+V02

= 0.8V1 + 0.5V2

Therefore a=0.8

b= 0.5

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