By using superposition principle:
Let V1 only active and V2 is open then,
V01 = (V1*20)/25
=0.8V1.
Now,let V2 only active V1 is open then,
V02 = (V2*20)/(20+20)
= 0.5 V2
According to superposition principle,
V0 = V01+V02
= 0.8V1 + 0.5V2
Therefore a=0.8
b= 0.5
Problem 5.3-1 5 Ohms 20 Ohms o20 Ohms 2 The inputs to this circuit are the...
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