(a)
Thus Chi square test statistic = 0.2 + 0.05 + 0.05 + 0 = 0.3
(b)
The degrees of freedom = (n-1) , since n = 4 , degrees of freedom = 3
(c)
at alpha = 0.05 level of significance, the critical chi square at 3 degrees of freedom = 7.815
However since the test statistic = 0.3 < 7.815, we fail to reject the null hypothesis. In order words we fail to reject that p1 = p2 = p3 = p4 = 1/4
Outcome Observed Expected20 20 20 20 ABCD만 18 Determine a) the χ test statistic b the...
Outcome Observed Expected404040 40 Determine test statistic, b) the degrees of freedom c) the critical value using α-0.05, and d) test the hypothesis at the α-0 05 level of significance. a) the χ 42 39 38 41 H,: At least one of the proportions is different from the others. (a) The test statistic is Type an exact answer.) (b) There aredegrees of freedom (c) The critical value is Round to three decimal places as needed.) (d) Should the null hypothesis...
12.1.7 Question Help Determine (a) the x? test statistic, (b) the degrees of freedom, (c) the critical value using a = 0.05, and (d) test the hypothesis at the c = 0.05 level of significance. DO Outcome Observed Expected А 51 50 B 46 50 с 51 50 52 50 Ho: PA=Pg Pc = Po = H, At least one of the proportions is different from the others. (a) The test statistic is 0.44 (Type an exact answer.) (b) There...
Determine (a) the χ2 test statistic, (b) test degrees of freedom, (c) the critical value using α=0.05, and (d) test the hypothesis at the α=0.05 level of significance. Outcome Observed Expected A 18 20 B 18 20 C 22 20 D 22 20 H0:Pa=Pb=Pc=Pd=1/4 H1: at least one of the proportions is different from the others. (a)test statistics is 0.8 (b) There are 3 degrees of freedom (c) The critical value is X ?? (round three decimal places as needed)...
Determine (a) the chi squared χ2 test statistic, (b) the degrees of freedom, (c) the critical value using α=0.05, and (d) test the hypothesis at the α=0.05 level of significance. H0: pA = pB = pC = pD = 1/4th H1: At least one of the proportions is different from the others. (a) The test statistic is __?__ . (Type an exact answer.)
Determine (a) the 2 test statistic, (b) the degrees of treedom, (c) the critical value using 0.05, and (d) test the hypothesis at the a 0.05 level of significance H: At least one of the proportions is different from the others. Outcome Observed Expected A B C D 44 36 37 43 40 40 40 40 We were unable to transcribe this image
Determine (a) the test statistic, (b) the degrees of freedom, (c) the P-alue, and (d) test the hypothesis at the a-0.05 level of significance. Outcome Obsenved Expected 25 25 25 25 A B C Do 22 28 24 26 H,: At least one of the proportions is different from the others Click the icon to wew the chi-square distribution table Round to two decimal places as needed.) (b) (True False) The number of degrees of freedom is oneless than the...
(a)-1,305 b)-0.872 #) Find the standardized test statistic + for a sample with M= 20, x= 10.9, 5= 2.0, and d.o.on if H, pl. 11.3. round answer 3 decimal places. C)-0.894 d)-1.233 #2) if a sample of 12 is drawn from a Normal population, what should be used as the test statistic? a) to with 13 degrees of freedom b) Zo with Il degrees of freedom C) to witn il degrees of freedom d) zo with lg digues of freedom...
11. A one-tailed hypothesis test with the t statistic a Aa Antisocial personality disorder (ASPD) is characterized by deceitfulness, reckless disregard for the well-being of others, a diminished capacity for remorse, superficial charm, thrill seeking, and poor behavioral control. ASPD is not normally diagnosed in children or adolescents, but antisocial tendencies can sometimes be recognized in childhood or early adolescence. James Blair and his colleagues have studied the ability of children with antisocial tendencies to recognize facial expressions that depict...
Please include degrees freedom with type of test statistic if applies. thank you!! answer all boxes please. Will rate Let p, and p, be the respective proportions of women with iron-deficiency anemia in each of two developing countries. A random sample of 1800 women from the first country yielded 500 women with iron-deficiency anemia, and an independently chosen, random sample of 2500 women from the second country yielded 764 women with iron-deficiency anemia. Can we conclude, at the 0.1 level...
On your first day on the job, your boss asks you to conduct a hypothesis test about the mean dwell time of a new type of UAV. Before you arrived, an experiment was conducted on ? = 5 UAVs (all of the new type) resulting in a sample mean dwell time of ?1 = 10.4 h????. The goal is to conclusively demonstrate, if possible, that the data supports the manufacturer’s claim that the mean dwell time is greater than 10...