Assume that I = 4.6A and d = 2.5cm .
- What is the strength of the magnetic field at the center of the loop in the figure?
- What is the direction of the magnetic field at the center of the loop?
Here ,
radius , r = 2.5/2
r = 1.25 cm = 0.0125 m
Now , strength of field ,
B = u0*I/(2*pi*r) + u0*I/(2r)
B= u0*4.6/(2*.0125) * (1/pi + 1)
B = 3.085 *10^-4 T
the strength of the magnetic field at the center of the loop is 3.085 *10^-4 T
the direction of field is INTO THE PAGE
r = d/2 = 2.5/2 = 1.25 cm = 0.0125 cm
Bnet = B(stright wire) + B(loop)
= mue*I/(2*pi*r) + mue*I/(2*r)
= 4*pi*10^-7*4.6/(2*pi*0.0125) + 4*pi*10^-7*4.6/(2*0.0125)
= 3.048*10^-4 T
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