Question

TO Homework 2 Chemical equil CHEM143P02-2010-1263- Hom2 Shop for Dresses Online - Over 3000 Styles _CHEM1043P02-2010-12683 At a given temperature, the equilibrium constant (K) for the decomposition of dinitrogen totraoxide to nitrogen dioxide is 0.212. If 0.525 atm N20, is sealed in a flask, what partial pressure (in atm) of NO, will exist at equilibrium? N2O4(g) = 2NO2 (9) Answer: -3.918 Check age Next page

Answer 1

10. 285 - 2 No₂ (9) Ep 0212 Nou Cal Initial pressure (atm) 0.525 Change - P Eguilibolum presupune 0.525 - +2P PNOL Prou 0.212 = (2P) ² 0.525 p 1 =) = (0.212 (0.525p) = up? (0.212) (0.525) - 0.212 p = 4e2 + 0.212p - 0.1113 42 = 0 pe - 0.212 - 6212)2 - 4(4) (-0.1113) 214) pe - 0212 + 1.35 1200947 Take 't' sign to get positive value of p. - 0212 + 1.351200947 0.142400118 At equilibrium (in atm/ PNo = 2 = 200.142 4oo 118) = 0.284800236 20.285 0.285