Question

after the explost Show the A 3 kg block Niides and with a speed H There fric between block and track the block at A- Find the normal force on Find the normal foror Use the work energy theorem to lind the frieuon as the block he trte tion force hat the magnitude oi ar 30 N, what is the areeleration as the block passes de and directio the total ion vector the direetion of a in clear diagram. At what rate the (e) Find the magni speed decreasing at B? nd a planet A satellite molves at constant sper ion T. Use Newton The time foc one o find lin terma. nd his law of uraversal the magnatude and direction of and Newton's gravitatsonal the accele remains constant in this The kinetle of the satellite orbit even though an (the acts on the satuation that enables the kinetic emergy to remain satellite. the farce the angular entum of the satellite (in terms of RT, and the mass Ms the mome the center of the ortut satellite) around an axis through change n this circular The angular mome um of the satelite doesn't Explain land in fact doesn't change actual (the gravitational force acts external why this is so even though the special property of the force that te [state precisely the sate of the satellite lar m enables the angu shown has a moment 30 pts The pulley 5 its rotation axis through and a radius R 0.2 ertia its center in the string is T tionless bearings. The tension 29.5 N-m is ex- 110 N. When an applied torque ented on the pulley of a handle, not shawn). It rotates counter-clockwise with an angular acceleratian a, and the mass m is raised, Find m. unable to do lal. and m in terms of a) much work is done by the applied torque t as the pulley

Answer 1

"Ans.1 mass of shell(m) = 10kg. Velority of the shell = 20m/s in(+) x-direction after explosion mass of shell is equally divided into two pieces.m1 = m2 = 5kg velocity of shell 1(v1) = 30m/s in(+) y-direction we use conservation of the moment for the shell as there are no external force acting during therefor momentum befor explasion = momentum after befor explosion momentum = 10 times(20) i kgm/s After explosion momentum = m1v1 + m2v2 m1 = 5 = m2 v1 = 30 = 5 times(30) j + 5v2 therefor 200i = 150j + 5v2 or v2 = 200i/5-150 = 40i-30j the magnitude of the velority for object 2