Question

Suppose you draw two cards with replacement. Round your answers to 3 significant digits*.

(a) What is the probability of getting a queen then a queen again?
P(queen on the first and queen on the second) =

(b) What is the probability of getting a queen then a jack?
P(queen on the first and jack on the second) =

(c) What is the probability of getting a queen then a spade?
P(queen on the first and spade on the second) =

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*Significant Digits: Here are some probabilities expressed to 3 significant digits.
You start counting digits from left to right starting with the first non-zero digit.

0.123      0.0123      0.00123      0.102      0.350      0.300

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Background playing card information: In a standard deck of playing cards there are 52 cards total.
There are 4 suits:

hearts ♥      diamonds ♦      spades ♠      clubs ♣     

Each suit has 13 values:

2  3  4  5  6  7  8   9  10  jack  queen  king  ace  

Answer 1

There are 52 cards in standard deck of playing cards. There are 4 suits which are hearts, diamonds, spades and clubs Each suit has 13 cards. 2345678 9 10 jack queen king ace. 13 The probability of each suit is, 52 The probability of getting jack or king or queen or ace is, 52 Consider that two cards drawn with replacement. a) The probability of getting a queen then a queen again is, Queen on the firstand queen on the secndqSirst) P(queen on the secnd) queen on the second 52 52 0.005917 Converted to three -0.00592 significant figures

b) The probability of getting a queen then a jack is, Queen on the first andP(queen on the fin st)x P(jack on the second) jack on the second 52 52 0.005917 Converted to three 0.00592 signi fi cant figures c) The probability of getting a queen then a spade is, pQueen on the firstand -P(queen on the first) x P(spade on the second = P(queen on the first)XP(spade on the second spade on the second 4 13 52 52 - 0.019231 Converted to three 0.0192 significant figures