At most, how many bright fringes can be formed on one side of the central bright fringe (not counting the central bright fringe) when light of 625 nm falls on a double slit whose spacing is
11 |
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9 |
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12 |
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10 |
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8 |
10 is the correct answer.
here is the expalnation
let n is is the maximum no of bright fringes formed.
for bright fringes, the path diffrence, d*sin(theta) = n*lamda (here d is silt separation and lamda is wavelelgnt)
for nth(maximum bright fringes) sin(theta) = sin(90)
so, d = n*lamda
n = d/lamda
= 6.77*10^-6/(625*10^-9)
= 10.8
here n should be integer.
so the answer is 10
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