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A boy exerts a force of 225 N on a lever to raise a 1.25 x...

A boy exerts a force of 225 N on a lever to raise a 1.25 x 103-N rock a distance of 13 cm. If the efficiency of the lever is 88.7%, how far did the boy move his end of the lever?

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Answer #1

efficiency = (W0 / Wi) . 100

                = (Frdr / Fede) .100

So de = Frdr .100 / Fe efficiency = (1.25 x 103 N)(0.13 m)(100) / (225 N)(88.7%)

         = 0.81m

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