5)
Object distance=u=4 cm
Radius of curvature of mirror=R=10 cm
Focal length of mirror= f=-10/2=-5 cm(negative because it is convex mirror)
1/u+1/v=1/f
1/4+1/v=1/-5
v=-2.22 cm
Image is formed on the same side as the object at a distance 2.22 cm from the mirror and is upright
6)
Distance between 2 mirror=5 m
Man is standimg halfway beyween the mirrors.
The first image he sees in the mirror he is facing will be equal to the distance beyween him and the mirror
First image is formed at 2.5 m into the mirror. Therefore from the man, the image is at 5 m
This image formed will be object for the other mirror
Distance between this image and the other mirror=2.5+5=7.5 m
Image formed in the other mirror will be 7.5 m into the other mirror. This will be object to form the second image in the mirror he is facing. The distance between this and the mirror he is facing=7.5+5=12.5 m
Image distance for second image=12.5 m measured from the mirror.
Distance between the man and this image=2.5+12.5=15 m
15 m is the required answer
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