Question

9. Given the following bond enthalpies, calculate the AHxn for the following reaction. 1. C2H4 + 302 > 2cO2 + 2H20 BOND C-H С

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9 Ans.

The reaction given is

C_{2}H_{4}+ 3O_{2}\rightarrow 2CO_{2}+ 2H_{2}O

Figure out how many bonds are broken and how many bonds are formed.

4 C-H bonds are broken

1 C=C bond is also broken

1 O=O bond per molecule is broken in 3 molecules of O2 (that is 3 O=O bonds are broken)

2 C=O bonds are formed in 1 molecule of CO2. So, in two molecules of CO2, the no. of C=O bonds formed is 4

2 O-H bond is formed per molecule of H2O. So, the number of O-H bonds formed in two molecules of H2O is 4

The enthalpy change of the reaction is

\Delta H_{rxn}= H_{b}-H_{f}

where Hb = sum of bond enthalpies of the bonds broken

Hf = sum of bond enthalpies of the bonds formed

Therefore,

\Delta H_{rxn}= [4(413)+614+3(495)]kJ/mol-[4(799)+4(463)]kJ/mol

\Delta H_{rxn}= [1652+614+1485]kJ/mol-[3196+1852]kJ/mol

\Delta H_{rxn}= 3751kJ/mol-5048kJ/mol

\Delta H_{rxn}= -1297 kJ/mol

Therefore, the enthalpy of the reaction is -1297kJ/mol

10 Ans.

MgCl2 has ionic bonding because the bonds are formed by the transfer of electrons from Mg to Cl.

HCl is covalent because the bond is formed by the sharing of an electron each from both the atoms. It is polar because the atoms have different electronegativities.

Cl2 is also covalent because the bond is formed by the sharing of electrons between the two atoms. It is non polar because there is no difference in electronegativities since both are Cl atom.

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