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John has a utility function given by the expression U(x) = E(r) -½A(s²). Where E(r) is...

John has a utility function given by the expression U(x) = E(r) -½A(s²). Where E(r) is the expected return on an asset and s is the standard deviation of returns on that asset.John has the opportunity to purchase the XJKsecurity that returns 25.9% with 23% probability and returns 8.6% the remainder of the time.

The security has a price of $33 and A=11

a) What is the risk-neutral valuation of the XJK security? Recall the risk-neutral value is simply the expected value.

b) Using the utility function above, find John's risk-averse valuation of XJK security. Hint: Find John's certainty equivalent (CEQ) for this security's payoff.

c) If the expected annual return on the market is 6.575%, the standard deviation of the market return is 8.9% and the risk-free rate for the next year is 1.22% then what is John's optimal percent of funds that he'll invest in the market?

d) Use the rates given in part c to answer this question. If a stock had a Beta of 2.92 what would be the expected return for that stock in the coming year?

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Answer #1

Part a)

U=E(r)-\frac{1}{2}As^{2}\\

John has the opportunity to purchase the XJKsecurity that returns 25.9% with 23% probability and returns 8.6% the remainder of the time. The security has a price of $33 and A=11

expected\ return=(0.23*0.259)+(0.086*0.77)=0.05957+0.06622=0.12579

expected return is 12.579%

risk\ neutral\ valuation\ of\ security=33*(1+0.12579)=37.15107\\

Part b)

\mu=\frac{0.259+0.086}{2}=0.1725

x_{i} P(x_{i}) (x_{i}-\mu)^{2}P(x_{i})
0.259 0.23 0.00172
0.086 0.77 0.005761

s=\sqrt{\sum{(x_{i}-\mu)^{2}P(x_{i})}}=\sqrt{0.005761+0.00172}=0.08649\\

expected\ utility\ of\ john=0.23(0.259-\frac{11*0.007481}{2})+0.77(0.086-\frac{11*0.007481}{2})=0.23*0.21785+0.77*0.04485=0.050105+0.03453=0.084635\\

Expected\ utility=0.084635\\ E(r)-\frac{1}{2}As^{2}=0.084635\\ E(r)=0.084635+\frac{11*0.08649}{2}=0.56033\\

risk\ averse\ valuation\ of\ XJK\ security=33*(1+.56033)=51.5

Part c)

If an investor in 2 assets and one of them is risk free and risk free asset has zero variance

then using slope of capital allocation line that is the sharpe ratio is

sharpe-ratio=\frac{R_{m}-R_{f}}{\sigma_{m}}=\frac{0.06575-0.0122}{0.089}=0.6016

John would invest 60.16 % of his funds in market

Part d)

expected\ return\ on\ XJK\ security,E(R_{xjk})=R_{m}+\beta_{xjk}(R_{m}-R_{f})\\ E(R_{xjk})=0.06575+2.92(0.06575-0.122)=0.222116

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