26) In Figure 8.4, a bullet of mass 0.01 kg moving horizontally strikes a block of...

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Question

Answer 1

Answer #1

Momentum before collision=momentum after collision

mv₁=(M+m)v

0.01*v₁=1.51*v

to find v use conservation of energy
0.5*1.51*v²=1.51*9.8*0.4

v=2.8 m/s

using in the initial equation

we get

v₁=(1.51/0.01)*2.8 = 422.8 m/s

Answer 2

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