Question

2. The gear train in Fig. 1 has a metric module of 8 mm/tooth and the following tooth numbers: N2 = 12, N3 = 36, N4 = 24, N5 = 38, and No= 26. If the transmitted load on Gear 2 is 58 N and the transmitted power is 40 kW, the rotational speed of the Gear 6 is most nearly which value? Counterclockwise (CCW) rotations are considered positive. N - Ng Fig. 1 3

Answer 1

m=8 N = 12, N= 36 Ny=24, Nr = 38, No=26 F=58N , P= 40kW. m= d. For 2 gear-2, 8 = dz - d, 48 mm 12 Power P = Tow but, T- Fidge - 58x 48 = 1392 N.mm = 1.392 Nm > 40 - 1.392 xw, w = 28.73 raden

aho N₂W2 = N₂ W3 12 (wy = w;-) a = 3. Ny. No wo N N NE la Ny. NG xw6 wz - Ny.NG Ne. Ng 24 X 26 w2= xwo 12x 38 War 1.368 wo کا =) Wo= 28.73 - 21 rad ls 1.368 11368 or w6= 21 x 60 rpm 20 Wo = 200.55 rpm Ave) Cve 1300
So, the closest answer is a, 187.7rpm