Mean = sum of numbers /n
n = 10
Sum of numbers
= 28.8
Mean = 28.8/10
= 2.88
The mean of 2.88 is the best point estimate for the class average
Provide an appropriate response. The grade point averages for 10 randomly selected students in a statistics...
Provide an appropriate response. Determine the sampling error if the grade point averages for 10 randomly selected students from a class of 125 students has a mean of x = 1.8. Assume the grade point average of the 125 students has a mean of u=2.4 Select one: o A. 0.6 O B. 1.5 O C.2.1 O D. -0.6
Provide an appropriate response. The grade point averages of students participating in sports at a local college are to be compared. The data are listed below. You wish to test the hypothesis that there is no difference in the mean grade point averages of the 3 groups. at a = 0.05.. What is the degrees of freedom? Hockey| Track) Basketball 3.0 3.2 2.1 2.5 3.5 3.1 2.6 1.8 1.9 2.1 3.3 2.7 2.8 2.5 2.5 df = (2, 12) df...
The grade point averages for 10 randomly selected high school students are listed below. Assume the grade point averages are normally distributed. 2.0, 3.2, 1.8, 2.9, 0.9, 4.0, 3.3, 2.9, 3.6, 0.8 Find a 98% confidence interval for the true mean.
The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed. 2.1, 3.1, 2.6, 1.5, 0.6, 4.0, 2.1, 1.1, 3.6, 0.5, 2.1, 3.4 construct a 90% confidence interval for the population mean The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) 2.1 below. 1.5 Assume the population is normally distributed. 2.1...
Homework: Section 2.4 -2.5 Score: 0 of 1 pt 10 of 22 (9 complete) 2.4.50 Sample grade point averages for ten male students and ten female students are listed. Find the coefficient of variation for each Males 2.5 3.7 3.6 3.9 2.6 3.3 3.8 1.9 D Females 2.9 3.6 2.1 3.8 3.4 3.9 3.9 3.8 2.3 The coefficient of variation for males is % (Round to one decimal place as needed.)
The grade point averages (GPA) of 18 randomly selected college students are used to estimate the mean GPA of the college students. The GPAs from the sample are as follows: 2.3 3.3 2.6 1.8 0.2 3.1 4.0 0.7 3.1 2.3 2.0 3.1 3.4 1.3 2.6 2.6 3.7 2.2 (5 points) Is it justified to use of the standard normal distribution to construct the confidence interval? Explain. (10 points) If the population is assumed to be normally distributed, construct a 98% confidence interval for the population mean GPA. Show your work in detail and use 3...
The grade point averages (GPA) for 15 randomly selected college students are: 2.3 3.3 2.6 1.8 0.2 3.1 0.7 4.0 2.3 2.0 3.1 3.4 13 26 26 Which of the following is the correct confidence interval procedure for a 95% confidence level?
The following are grade point averages (GPAs) for a sample of students in a scholarship competition: 3.6, 3.8, 3.6, 3.9, 2.6, 3.8, 3.8, 3.9. a. Organize the data into a frequency distribution table. b. Using this frequency distribution format, calculate the mean and the standard deviation (using the direct method). c. Is there something peculiar in this distribution? Adjust for it by recalculating the statistics. d. Comment on the differences betrveen the original statistics and the adiusted statistics. plz write...
The table below gives the birth weights in pounds of piglets in 8 randomly selected litters from large number of litters in a state. Litter 1 2 3 4 5 6 7 8 2.0 3.5 3.3 3.2 2.6 3.1 2.6 2.5 2.8 2.8 1.6 3.3 2.6 2.9 2.2 2.4 3.3 3.2 3.6 3.2 2.9 3.1 2.2 3.0 3.2 3.5 3.1 1.9 2.0 2.5 2.5 1.5 4.4 2.3 3.2 3.3 2.0 1.2 3.6 2.4 3.3 2.5 2.1 1.2 1.9 2.0 2.9 ...
6. The grade point averages (GPA) for 15 randomly selected college students are: 3.3 2.6 1.8 0.2 3.1 0.7 2.3 4.0 2.3 2.0 3.1 3.4 13 26 26 Which of the following is the correct confidence interval procedure for a 95% confidence level? A. SRS Normal told so o known * = 6.25 o=8.52 n= 15 95% CI Zinterval At the 95% confidence level, u is in (1.94, 10.565) B. SRS Normal by QQ graph * = 6.25 s=8.52 n=...