The grade point averages for 10 randomly selected high school students are listed below. Assume the grade point averages are normally distributed. 2.0, 3.2, 1.8, 2.9, 0.9, 4.0, 3.3, 2.9, 3.6, 0.8 Find a 98% confidence interval for the true mean.
Solution :
We have,
= 25.7 / 10 = 2.57
s = 1.145
n = 10
df = 10 - 1 = 9
t /2,df = 2.896
Margin of error = E = t/2,df * (s /n)
= 2.896 * (1.145 / 10)
Margin of error = E = 1.05
The 98% confidence interval estimate of the population mean is,
- E < < + E
2.57 - 1.05 < < 2.57 + 1.05
1.52 < < 3.62
(1.52 , 3.62)
The grade point averages for 10 randomly selected high school students are listed below. Assume the...
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