Question

C linux

please write it by only using “if and else” conditions, thanks so much

Requirements 1. Copy your solution for Task 3 t3.c to a new file t4.c. 2. The input is guaranteed to contain at least one non-whitespace character. 3. If the input is well-formed, i.e., can be parsed to a number, the program should behave identically to Task 3. All the requirements of Task 3 still apply except the file name. 4. If the input is not well formed, the program should print a helpful error message that contains the value returned by scanf so that the programmer can compare this number with the scanf documentation to figure out what went wrong. (If this program was aimed at end-users, we might design this differently). 5. The error message should be in the form: "scanf error: %d)\n" with the scanf return value between the parentheses. 6. Sample input: 3.1415 7. Corresponding output: 3 34 8. Sample input: sausage 9. Corresponding output: scanf error: (0) 10. Be careful about the spaces, for instance, the space between the : and (in the error string. Guide You should test the return value of scanf to decide whether a floating point value was detected in the input.

this is my task 3

Answer 1

#include<stdio.h>
#include<math.h>

int main()
{
   float i;
   int input = scanf("%f",&i);     // input will contain the return value of scanf() function if its zero then if condition gets true
   if(input == 0)
   {
       printf("scanf error: (%d)\n",input);
   }
   else
   {
   int x = floor(i);
   int y = round(i);
   int z = ceil(i);
  
   printf("%d ",x);
   printf("%d ",y);
   printf("%d\n",z);
   }
   return 0;
}

input : sausage

output :

scanf error: (0)

input : 3.14

output : 3 3 4