STOCKROOM PROVIDED SOLUTIONS: lodine solution: (0.005 mo Starch indicator solution: (0.5%).
If 0.5 mol NaOH are necessary to turn the indicator in a solution pink, how many moles of KHP have reacted?
1. Why is the starch indicator added to the reaction solution? 2. Consider the following balanced chemical reaction: 2 MnO, (aq) + 5 H2O2(aq) + 6 H*(aq) → 2 Mn2+ (aq) + 5 O2(g) + 8 H,O(1) a. A student wrote the following rate law for this reaction: Rate = k [MnOz]”[H202]*[H+]6 Is this correct? Explain. b. Briefly describe what must be done to obtain the correct rate law. 3. Define the following terms: a. Rate: b. Rate law: c....
3) Use the mole ratios contained in both equation 3 and equation 4 to calculate the volume (in mL) of 0.0100 M potassium iodate solution needed to completely oxidize all of the ascorbic acid contained in 20.00 mL of 0.0200 M ascorbic acid solution. concentration of the titrant can be used along with the mole ratios from the reaction equations to determine the amount of ascorbic acid in the solution Chemical Reactions involved with the redox titration: Equation 1 shows...
Experiment 2: Diffusion Concentration Gradients and Membrane Permeability Data Tables Table 2: Indicator Reagent Data Indicator Starch Positive Starch Negative Glucose Positive Glucose Negative Glucose Test Strip n/a n/a green yellow IKI Solution dark blue light brown n/a n/a Table 3: Diffusion of Starch and Glucose Over Time Indicator Dialysis Bag After 60 Minutes Beaker Water After 60 Minutes Glucose Test Strip yellow green ( if all glucose passed to the beaker from the bag) IKI from incolore changed to...
Universal indicator is a solution which contains several acid base indicators and provided sufficient color changes to estimate pH over a wide range. One such indicator contains a mixture of thymol blue, phenolphthalein, and methl orange. Determine the color of this indicator at a) pH=1.5, b) pH=4, c) pH 6.5, d) pH=9, and e) pH=11.5. Explain reasoning.
(ii) SCN solution. You are provided with a 0.5 M solution. Calculate the volume of solution required to give final SCN concentrations of: Final (SCN) 0.01 0.05 0.10 0.20 0.30 0.40 Volume 0.5 M solution needed For this type of calculation always work from the number of moles of SCN required. (iii) Sufficient 3 M HNO3 to make the final solution 0.2 M with respect to HNO3. The volume of HNO3 required is — _ml.
6. Dialysis bags containing a 0.5% sucrose solution are placed in beakers containing the sucrose solutions indicated below. Dialysis bags are NOT permeable to sucrose. -0.5% -0.5% sucrose 0.5% sucrose sucrose -Pure water -0.5% sucrose 1.5% sucrose Chades MN, LLC Indicate the letter of the beaker (A, B, or C) in which the following events or situations occur. a. The dialysis bag remains the same size. b. The dialysis bag shrinks. C. Water moves from the beaker into the dialysis...
ycof 62.07g/mo 2. Freezing point of solutions Molality ofTheoretical Experimn. Freezing Average F.P Solution Freezing Pt Point (1&2) 0.0℃10.1と 3.62S 6 114 9.667 4.S0 164C-196 125.7 EXAMPLE CALCULATION OF theoretical freezing point of solution (dH20=1.00g/mL dethylenegyco#1.11g/mL k, H20: 1.86°C/nt):
Use stock solution of 0.5 M CuSO4 to make up the following solutions by serial dilution to a final volume of 1 ml: 50mM, 5mM, 0.5mM, and 0.05mM Please show 'how many DI water 0.5M CuSO4 needed to be used?'
1. Methyl orange, HMO, is a common acid-base indicator. In solution it ionizes according to the equation: HMO(aq) = H(aq) + MO"(aq) red yellow If methyl orange is added to distilled water, the solution turns yellow. If a drop or two of 6 M HCl is added to the yellow solution, it turns red. If to that solution one adds a few drops of 6 M NaOH the color reverts to yellow a. Why does adding 6 M HCl to...