Question

423. In the illustration, a hollow coil of coated wire is connected to a galvanometer that measures small electric currents. A strong magnet moves to the left into the coil and through the coil, then exits the coil on the left. What would be the readings on the galvanometer? N S (A) The galvanometer would register a current in one direction as the (B) The galvanometer would register a current in one direction the entire (C) The galvanometer would register a current in one direction as the (D) No current would be produced in the coil. magnet enters the coil and then read zero as the magnet moves through and exits the coil. time, as the magnet enters the coil, moves through the coil, and exits the coil-decreasing to zero as the magnet moves far away. magnet enters the coil and register a current in the opposite direction as the magnet leaves the coil.

Answer 1

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As magnet enters and exits in both cases change in flux occurs through coil and emf is induced in the coil as per faraday's law of EM - Induction If magnet enters flux linked with coil increases so current Induces in counter - clockwise direction to minimize the effect of flux increment (As per Lenz's law) If magnet exit then flux linked with coil decreases and so current induces in clockwise direction So, During both entering & exiting the magnet current induces but in opposite direction So option (C) is true Answer A = 0.25 m^2, f = 10 xz w = 2 pi f = 20 pi rad/sec B = 8 T Therefore (e)_max = B AW = 80 times 0.25 times 20 pi = 1256.64 V Answer No option Matched as per given data emf Induced in rotating loop is e = NBAW sin wt maximum emf Here,